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How can I use inverse or negative wildcards when pattern matching in a unix/linux shell?
...are not also in set 2, ls *Music*. This requires both sets to be in sorted order to work properly. No problem for ls and glob expansion, but if you're using something like find, be sure to invoke sort.
comm -23 <(find . | sort) <(find . | grep -i '.jpg' | sort)
Potentially useful.
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Eclipse: have the same file open in two editors?
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In order to keep answers up to date i underline that with Eclipse STS this action is performed using window -> Editor -> Toggle split editor (horizental) | Toggle split editor (vertical)
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Can you give a Django app a verbose name for use throughout the admin?
...p_name = app_label
While you are tweaking the index view why not add an 'order' property too.
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How to avoid the “divide by zero” error in SQL?
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In order to avoid a "Division by zero" error we have programmed it like this:
Select Case when divisor=0 then null
Else dividend / divisor
End ,,,
But here is a much nicer way of doing it:
Select dividend / NULLIF(divisor, 0...
Difference between View and table in sql
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GIT commit as different user without email / or only email
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This is the only one that worked for me. Note the order is important. git commit -c user.name="j bloggs" -am "message" gives an error fatal: Option -m cannot be combined with -c/-C/-F
– Martin
Jul 10 at 9:14
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Unexpected character encountered while parsing value
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This issue is related to Byte Order Mark in the JSON file. JSON file is not encoded as UTF8 encoding data when saved. Using File.ReadAllText(pathFile) fix this issue.
When we are operating on Byte data and converting that to string and then passing to J...
How to sort by two fields in Java?
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You can use Collections.sort as follows:
private static void order(List<Person> persons) {
Collections.sort(persons, new Comparator() {
public int compare(Object o1, Object o2) {
String x1 = ((Person) o1).getName();
String x2 = ((Person) o2)...
.append(), prepend(), .after() and .before()
...ng jQuery
</div>
So although these functions flip the parameter order, each creates the same element nesting:
var $div = $('<div>').append($('<img>'));
var $img = $('<img>').appendTo($('<div>'))
...but they return a different element. This matters for method cha...
Windows path in Python
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