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How can I determine the current line number in JavaScript?
...
You can use:
function test(){
console.trace();
}
test();
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NSLog the method name with Objective-C in iPhone
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In Swift 4:
func test(){
print(#function)
}
test() //print the value "test()"
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Delete multiple remote branches in git
...this. Answers to those questions address the same problem, you may want to test the solutions yourself.
– neevek
May 11 '12 at 17:11
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At runtime, find all classes in a Java application that extend a base class
...ass) {
List list = aClass.newInstance();
list.add("test");
System.out.println(list.getClass().getName() + ": " + list.size());
}
}
}
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How can strings be concatenated?
...y it seems to have been optimized since the article you cite. From a quick test with timeit, I wasn't able to reproduce the results.
– tonfa
May 28 '11 at 15:05
3
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var self = this?
...rror and this refers to your desired scope in your instance.
this.name = 'test'
myObject.doSomething(data => {
console.log(this.name) // this should print out 'test'
});
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Why is null an object and what's the difference between null and undefined?
...undefined, null
Booleans: false
Numbers: +0, -0, NaN
Strings: ""
You can test the conversion to boolean by using Boolean as a function (normally it is a constructor, to be used with new):
> Boolean(null)
false
> Boolean("")
false
> Boolean(3-3)
false
> Boolean({})
true
> Boolean([]...
Typing Enter/Return key using Python and Selenium?
... and Enter or Return key in Selenium. Unfortunately the form I'm trying to test (not my own code so I can't modify) doesn't have a Submit button. When working with it manually, I just type ENTER or RETURN . I need to know how to do that with the Selenium type command as there is no button to cl...
Use CSS3 transitions with gradient backgrounds
...some browser releases that supported transitions on gradients (e.g IE10. I tested gradient transitions in 2016 in IE and they seemed to work at the time, but my test code no longer works.)
Update: October 2018
Gradient transitions with un-prefixed new syntax [e.g. radial-gradient(...)]now confirmed...
Is there a ceiling equivalent of // operator in Python?
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In quick tests, #1 is the fastest here, even compared to -(-a // b) o_O
– endolith
Feb 4 at 5:00
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