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MVC pattern on Android
Is it possible to implement the model–view–controller pattern in Java for Android?
21 Answers
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How do I keep CSS floats in one line?
I want to have two items on the same line using float: left for the item on the left.
10 Answers
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How does a hash table work?
...xplanation in layman's terms.
Let's assume you want to fill up a library with books and not just stuff them in there, but you want to be able to easily find them again when you need them.
So, you decide that if the person that wants to read a book knows the title of the book and the exact title to...
Cutting the videos based on start and end time using ffmpeg
...code differences from other frames, they require all of the data starting with the previous keyframe.
With the mp4 container it is possible to cut at a non-keyframe without re-encoding using an edit list. In other words, if the closest keyframe before 3s is at 0s then it will copy the video starti...
Android Studio vs Eclipse + ADT Plugin? [closed]
...e for using IntelliJ over Android Studio is if you're using the Ultimate edition. It has a lot more plugins that you can use with the IDE. If you're using the Ultimate edition already and don't want to use two IDE's simultaneously, there is no reason to switch over to Android Studio (except bleeding...
Why is lazy evaluation useful?
... I have yet to have anyone explain to me in a way that makes sense; mostly it ends up boiling down to "trust me".
22 Answer...
Has Facebook sharer.php changed to no longer accept detailed parameters?
We have been opening a sharing popup (via window.open) with the URL like
5 Answers
5
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Can I use git diff on untracked files?
Is it possible to ask git diff to include untracked files in its diff output, or is my best bet to use git add on the newly created files and the existing files I have edited, then use:
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Can I squash commits in Mercurial?
I have a pair of commits that should really be just one. If I was using git, I would use:
8 Answers
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How to check in Javascript if one element is contained within another
... answers as well.
Old answer:
Using the parentNode property should work. It's also pretty safe from a cross-browser standpoint. If the relationship is known to be one level deep, you could check it simply:
if (element2.parentNode == element1) { ... }
If the the child can be nested arbitrarily d...