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Cleanest way to get last item from Python iterator
...t? If the iterator doesn't actually iterate, then an out-of-band value is more meaningful than some misleading function-specific default.
– S.Lott
Jan 26 '10 at 11:44
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Generate all permutations of a list without adjacent equal elements
...introducing additional defects to begin with x. If the first substring has more y's than x's, then some other substring has more x's than y's, and we can rewrite these substrings without additional defects so that x goes first. In both cases, we find an optimal solution T that extends P', as needed....
How to use if-else option in JSTL
... Aside from the wrapper tag (choose), I don't see how this is any more verbose than if/elseif/else would be. One wrapper tag hardly constitutes 'clunky as hell', no?
– Steven Benitez
Jan 8 '11 at 18:25
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Incrementing in C++ - When to use x++ or ++x?
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unix domain socket VS named pipes?
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UNIX-domain sockets are generally more flexible than named pipes. Some of their advantages are:
You can use them for more than two processes communicating (eg. a server process with potentially multiple client processes connecting);
They are bidirectional;...
jQuery's jquery-1.10.2.min.map is triggering a 404 (Not Found)
... frustration if you don't like dealing with variable names like a and c.
More about sourcemaps here: An Introduction to JavaScript Source Maps
Dodge: disable sourcemaps
Instead of getting the files, you can alternatively disable JavaScript source maps completely for now, in your settings. This i...
Show just the current branch in Git
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Link to the issue number on GitHub within a commit message
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Closure in Java 7 [closed]
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Do you have a more specific link than the overall blog?
– I82Much
Nov 11 '14 at 4:50
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Way to go from recursion to iteration
.../ Push other objects on the stack as needed.
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}
Note: if you have more than one recursive call inside and you want to preserve the order of the calls, you have to add them in the reverse order to the stack:
foo(first);
foo(second);
has to be replaced by
stack.push(second);
stack.push(first...