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Difference between Django's annotate and aggregate methods?

...gt; q = Book.objects.annotate(num_authors=Count('authors')) >>> q[0].num_authors 2 >>> q[1].num_authors 1 q is the queryset of books, but each book has been annotated with the number of authors. share ...
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How to implement has_many :through relationships with Mongoid and mongodb?

... | edited Aug 13 '11 at 20:31 answered Aug 13 '11 at 20:06 ...
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Django self-referential foreign key

... Zags 23.1k1010 gold badges7272 silver badges103103 bronze badges answered Mar 8 '13 at 2:25 Jared ForsythJared F...
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Cannot send a content-body with this verb-type

I just got this exception (ProtocolViolationException) in my .NET 2.0 app (running on windows mobile 6 standard emulator). What confuses me is that as far as i know, I have not added any content body, unless I've inadvertently done it somehow. My code is below (very simple). Is there anything els...
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How do I download a tarball from GitHub using cURL?

...on to follow redirects: curl -L https://github.com/pinard/Pymacs/tarball/v0.24-beta2 | tar zx share | improve this answer | follow | ...
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how to use XPath with XDocument?

...ame); var name = document.Descendants(XName.Get("Name", @"http://demo.com/2011/demo-schema")).First().Value; If you are sure that XPath is the only solution you need: using System.Xml.XPath; var document = XDocument.Load(fileName); var namespaceManager = new XmlNamespaceManager(new NameTable());...
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Generate full SQL script from EF 5 Code First Migrations

...nager Console works as expected: Update-Database -Script -SourceMigration:0 share | improve this answer | follow | ...
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Rails filtering array of objects by attribute value

...html#method-i-partition – Vlad Jun 20 '16 at 21:04 Thanks @Vlad, thats cool, but it support only if we need to collect...
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Can you resolve an angularjs promise before you return it?

... | edited Nov 2 '15 at 5:02 Simon East 42.7k1313 gold badges124124 silver badges116116 bronze badges an...
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Parsing a comma-delimited std::string [duplicate]

...ss.peek() == ',') ss.ignore(); } for (std::size_t i = 0; i < vect.size(); i++) std::cout << vect[i] << std::endl; } share | improve this answer ...