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How to prevent caching of my Javascript file? [duplicate]
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Add a random query string to the src
You could either do this manually by incrementing the querystring each time you make a change:
<script src="test.js?version=1"></script>
Or if you are using a server side language, you could automatically generate this:
ASP.NET:
<scri...
PostgreSQL: How to change PostgreSQL user password?
...ostgresql/9.1/main/pg_hba.conf (path will differ) and change:
local all all peer
to:
local all all md5
Then restart the server:
$ sudo service postgresql restart
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How can I group data with an Angular filter?
...DATE: jsbin Remember the basic requirements to use angular.filter, specifically note you must add it to your module's dependencies:
(1) You can install angular-filter using 4 different methods:
clone & build this repository
via Bower: by running $ bower install angular-filter from ...
What does cmd /C mean? [closed]
...iable expansion using ! as the
delimiter. For example, /V:ON would allow !var! to expand the
variable var at execution time. The var syntax expands variables
at input time, which is quite a different thing when inside of a FOR
loop.
/V:OFF Disable delayed environmen...
Get JSON object from URL
...json);
echo $obj->access_token;
For this to work, file_get_contents requires that allow_url_fopen is enabled. This can be done at runtime by including:
ini_set("allow_url_fopen", 1);
You can also use curl to get the url. To use curl, you can use the example found here:
$ch = curl_init();
//...
py2exe - generate single executable file
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PyInstaller will create a single .exe file with no dependencies; use the --onefile option. It does this by packing all the needed shared libs into the executable, and unpacking them before it runs, just as you describe (EDIT: py2ex...
Automate ssh-keygen -t rsa so it does not ask for a passphrase
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On RHEL 6, I got this error: "ssh-keygen: option requires an argument -- N" :(
– Anthony O.
Dec 9 '15 at 15:02
1
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Inject service in app.config
...e into app.config, so that data can be retrieved before the controller is called. I tried it like this:
10 Answers
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How to parse an RSS feed using JavaScript?
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Parsing the Feed
With jQuery's jFeed
(Don't really recommend that one, see the other options.)
jQuery.getFeed({
url : FEED_URL,
success : function (feed) {
console.log(feed.title);
// do more stuff here
}
});
With jQuer...
Example of multipart/form-data
...6 is two hyphens shorter then the actual boundaries in the data. This is really, really hard to see with all the hyphens strung together.
– Fake Name
Jun 2 '17 at 6:39
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