大约有 43,410 项符合查询结果(耗时:0.0382秒) [XML]

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List of lists into numpy array

... 205 If your list of lists contains lists with varying number of elements then the answer of Ignaci...
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Syntax behind sorted(key=lambda: …)

...at of def to create a function. adder_lambda = lambda parameter1,parameter2: parameter1+parameter2 def adder_regular(parameter1, parameter2): return parameter1+parameter2 lambda just gives us a way of doing this without assigning a name. Which makes it great for using as a parameter to a function...
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Callback functions in C++

...sing appropriate callables for example: std::vector<double> v{ 1.0, 2.2, 4.0, 5.5, 7.2 }; double r = 4.0; std::for_each(v.begin(), v.end(), [&](double & v) { v += r; }); std::for_each(v.begin(), v.end(), [](double v) { std::cout << v << " "; }); which prints 5 6.2 8 9.5...
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Unix's 'ls' sort by name

...bashrc - .config - .local - Downloads - can - tmp – 12431234123412341234123 Aug 14 '17 at 10:15 1 ...
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Using awk to print all columns from the nth to the last

... 24 Answers 24 Active ...
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Create a dictionary with list comprehension

...y: value for (key, value) in iterable} Note: this is for Python 3.x (and 2.7 upwards). Formerly in Python 2.6 and earlier, the dict built-in could receive an iterable of key/value pairs, so you can pass it a list comprehension or generator expression. For example: dict((key, func(key)) for key in ...
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What is the difference between print and puts?

...ot one already. print does not add a new line. For example: puts [[1,2,3], [4,5,nil]] Would return: 1 2 3 4 5 Whereas print [[1,2,3], [4,5,nil]] would return: [[1,2,3], [4,5,nil]] Notice how puts does not output the nil value whereas print does. ...
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How to get all subsets of a set? (powerset)

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Remove an entire column from a data.frame in R

... 421 You can set it to NULL. > Data$genome <- NULL > head(Data) chr region 1 chr1 CD...
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Equation for testing if a point is inside a circle

... In general, x and y must satisfy (x - center_x)^2 + (y - center_y)^2 < radius^2. Please note that points that satisfy the above equation with < replaced by == are considered the points on the circle, and the points that satisfy the above equation with < replaced ...