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jsoncpp 不能处理__int64(long long)类型数据 - C/C++ - 清泛网 - 专注C/C++及内核技术
jsoncpp 不能处理__int64(long long)类型数据jsoncpp，是一个c++的解析和生成json的开源工具。如果你的c++程序需要解析或生成json，它会使这个过程变得很简单！但是，今天在用jsoncpp进...jsoncpp，是一个c++的解析和生成json的开源工具。如...
MongoDB仿关系型数据库Group聚合例子 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...数据
Dictionary dic = new Dictionary();
dic["_userName"] = ""; // 与原字段名区分开
dic["_date"] = "";
dic["_data"] = "0";
MongoServer server = new MongoClient(MongoConnStr).GetServer();
MongoDatabase db = serve...
Visual Studio 2013 Update 4【VS2013 SP4 旗舰版下载地址】 - 更多技术 - ...
...(Chinese-Simplified)：7255 MB
发布日期： 2014/11/12
文件名： cn_visual_studio_ultimate_2013_with_update_4_x86_dvd_5935081.iso
语言： Chinese - Simplified
SHA1：5F924E3B8F6715F92DCD2F8E58558833D310A146
http://download.microsoft.com/do ... s2013.4_ult_chs.iso
Visual Studio Ultima...
Visual Studio 2013 Update 4【VS2013 SP4 旗舰版下载地址】 - 其他 - 清泛...
...(Chinese-Simplified)：7255 MB
发布日期： 2014/11/12
文件名： cn_visual_studio_ultimate_2013_with_update_4_x86_dvd_5935081.iso
语言： Chinese - Simplified
SHA1：5F924E3B8F6715F92DCD2F8E58558833D310A146
http://download.microsoft.com/do ... s2013.4_ult_chs.iso
Visual Studio Ultima...
How do I get class name in PHP?
.... I found this out by trying to access the ::class property(?) of a dynamically generated class and getting the following error: Dynamic class names are not allowed in compile-time ::class fetch. See this answer for more details. I also found this note from the docs helpful.
–...
How can I mock dependencies for unit testing in RequireJS?
...'log');
yourModule.foo();
expect(console.log).toHasBeenCalledWith('hurp');
})
});
});
})();
So I'm using this approach in production for a while and its really robust.
share
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Given a view, how do I get its viewController?
...nd
This macro avoids category pollution:
#define UIViewParentController(__view) ({ \
UIResponder *__responder = __view; \
while ([__responder isKindOfClass:[UIView class]]) \
__responder = [__responder nextResponder]; \
(UIViewController *)__responder; \
})
...
Package objects
...
Normally you would put your package object in a separate file called package.scala in the package that it corresponds to. You can also use the nested package syntax but that is quite unusual.
The main use case for package object...
Is it possible to use getters/setters in interface definition?
At the moment, TypeScript does not allow use get/set methods(accessors) in interfaces.
For example:
4 Answers
...
Add a property to a JavaScript object using a variable as the name?
...out modifying but it's referenced by other questions that are about dynamically creating objects and so I ended up here and happily benefited from this answer.
– Oliver Lloyd
Oct 29 '16 at 17:40
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