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Check if all elements in a list are identical
...t, for Python 2.7 and (only s1, s4, s7, s9 should return True)
s1 = [1] * 5000
s2 = [1] * 4999 + [2]
s3 = [2] + [1]*4999
s4 = [set([9])] * 5000
s5 = [set([9])] * 4999 + [set([10])]
s6 = [set([10])] + [set([9])] * 4999
s7 = [1,1]
s8 = [1,2]
s9 = []
we get
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edited Sep 14 '15 at 11:33
Balthazar
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answered Oct 13 '11 at 4:25
CandideCandide
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159
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