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Getting the class name of an instance?
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Do you want the name of the class as a string?
instance.__class__.__name__
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In Perl, how can I read an entire file into a string?
I'm trying to open an .html file as one big long string. This is what I've got:
16 Answers
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Is there YAML syntax for sharing part of a list or map?
...t;< : *sites # merge *sites into this mapping
? www.baz.com # add extra stuff
Some things to notice. Firstly, since << is a key, it can only be specified once per node. Secondly, when using a sequence as the value, the order is significant. This doesn't matter in the example here, s...
ImportError: Cannot import name X
...es that have not been defined yet, that
definition may be expressed as a string literal, to be resolved later.
and remove the dependency (the import), e.g. instead of
from my_module import Tree
def func(arg: Tree):
# code
do:
def func(arg: 'Tree'):
# code
(note the removed import ...
Which characters are valid in CSS class names/selectors?
...lready separate classes from each other.
So, if you need to turn a random string into a CSS class name: take care of NUL and space, and escape (accordingly for CSS or HTML). Done.
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Get current time as formatted string in Go?
What's the best way to get the current timestamp in Go and convert to string? I need both date and time in eg. YYYYMMDDhhmmss format.
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Removing a list of characters in string
I want to remove characters in a string in python:
18 Answers
18
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Detect if device is iOS
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Detecting iOS
With iOS 13 iPad both User agent and platform strings are changed and differentiating between iPad and MacOS seems possible, so all answers below needs to take that into account now.
This might be the shortest alternative that also covers iOS 13:
function iOS() {
retur...
Rails 4 LIKE query - ActiveRecord adds quotes
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Your placeholder is replaced by a string and you're not handling it right.
Replace
"name LIKE '%?%' OR postal_code LIKE '%?%'", search, search
with
"name LIKE ? OR postal_code LIKE ?", "%#{search}%", "%#{search}%"
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How to get the parent dir location
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os.path.abspath doesn't validate anything, so if we're already appending strings to __file__ there's no need to bother with dirname or joining or any of that. Just treat __file__ as a directory and start climbing:
# climb to __file__'s parent's parent:
os.path.abspath(__file__ + "/../../")
That...