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How do you version your database schema? [closed]
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Brazil looks pretty good, too bad I'm using mainly PHP. Ever considered porting the system?
– Eran Galperin
Jan 1 '09 at 20:26
add a comment
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Remove all but numbers from NSString
... is called NSScanner. It's used as follows:
NSString *originalString = @"(123) 123123 abc";
NSMutableString *strippedString = [NSMutableString
stringWithCapacity:originalString.length];
NSScanner *scanner = [NSScanner scannerWithString:originalString];
NSCharacterSet *numbers = [NSCharact...
Test if string is a number in Ruby on Rails
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\Z allows to have \n at the end of the string, so "123\n" will pass validation, regardless that it's not fully numeric. But if you use \z then it will be more correct regexp: /\A\d+\z/
– SunnyMagadan
Aug 14 '17 at 9:14
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Using Html.ActionLink to call action on different controller
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Craig StuntzCraig Stuntz
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IIS_IUSRS and IUSR permissions in IIS8
...IS worker processes run third-party code by default (Classic ASP, ASP.NET, PHP code), it was time to isolate IIS worker processes from other Windows system services and run IIS worker processes under unique identities. The Windows operating system provides a feature called "Virtual Accounts" that al...
使用CSplitterWnd实现拆分窗口（多视图显示） - C/C++ - 清泛网 - 专注C/C++及内核技术
...,"引擎",LVCFMT_LEFT,200,0);
int pos;
pos = ptheList->InsertItem(0,"123");
ptheList->SetItemText(pos,1,"http:\\\\");
ptheList->SetItemText(pos,2,"Google");
}
编译通过就可以发现每个窗口都按我们的要求进行了划分和初始化
//获取主窗口
CMainFrame* pFram...
Can I call a base class's virtual function if I'm overriding it?
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123
Yes,
class Bar : public Foo
{
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void printStuff()
{
Foo::printStuff();...
How do I detect IE 8 with jQuery?
...ersion >= 8.0) { dosomething} I am not sure it will work for version 8.123.45.6 or will it?
– salmane
Feb 4 '10 at 19:08
13
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How do I concatenate multiple C++ strings on one line?
...tring s = string("abc").append("def").append(otherStrVar).append(to_string(123));
– Patricio Rossi
Nov 12 '17 at 2:46
1
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How do I dynamically assign properties to an object in TypeScript?
.../ the following is an error,
// so you haven't lost type safety
foo.bar = 123;
Alternatively you can mark these properties as optional:
interface IFoo{
bar?:string;
baz?:string;
boo?:string;
}
// Now your simple initialization works
var foo:IFoo = {};
Try it online
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