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Convert JSON string to dict using Python
...e bit confused with JSON in Python.
To me, it seems like a dictionary, and for that reason
I'm trying to do that:
4 Answers...
How to make remote REST call inside Node.js? any CURL?
...book.com .... } not {host: http: graph.facebook.com }. That tripped me up for a few cycles. (See below). These are both great answers. Thanks to you both.
– binarygiant
Mar 7 '13 at 21:00
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Send POST data using XMLHttpRequest
...amp;name=binny';
http.open('POST', url, true);
//Send the proper header information along with the request
http.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
http.onreadystatechange = function() {//Call a function when the state changes.
if(http.readyState == 4 &&a...
setBackground vs setBackgroundDrawable (Android)
I want to set background drawable of a view. There are two methods for this (as far as I see): setBackground and setBackgroundDrawable .
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Start ssh-agent on login
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This script worked for me when I put it in my ~/.bashrc file (not my ~/.profile or ~/.bash_profile). The first time I open a local console it prompts for the passphrase, everything works from that point on without further prompting. Cheers.
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Convert a Map to a POJO
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Well, you can achieve that with Jackson, too. (and it seems to be more comfortable since you were considering using jackson).
Use ObjectMapper's convertValue method:
final ObjectMapper mapper = new ObjectMapper(); // jackson's objectmapper
final MyPojo pojo = mapper.convertValue(map, MyPojo.class...
Proper way to initialize a C# dictionary with values?
...ers weren't introduced until C# 3.0. The detail as to why it didn't work before has already been answered.
– James
Jun 11 '13 at 15:20
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Is there a way to style a TextView to uppercase all of its letters?
...time. What a Total Failure. lol
Update
You can now use
textAllCaps
to force all caps.
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How to get a string after a specific substring?
... need to split a text with the 'low' word and it contains the word lower before it, this will not work!
– Leonardo Hermoso
Jan 12 '17 at 3:48
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How to activate “Share” button in android app?
...tivity(Intent.createChooser(sharingIntent, "Share via"));
Useful links:
For basic sharing
For customization
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