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Should I use .done() and .fail() for new jQuery AJAX code instead of success and error
...jqXHR.success() have some load time in callback and sometimes can overkill script. I find that on hard way before.
UPDATE:
Using jqXHR.done(), jqXHR.fail() and jqXHR.always() you can better manipulate with ajax request. Generaly you can define ajax in some variable or object and use that variable ...
How to terminate the script in JavaScript?
How can I exit the JavaScript script much like PHP's exit or die ? I know it's not the best programming practice but I need to.
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Download a file by jQuery.Ajax
...h is completely right about this, you can't do it through Ajax because JavaScript cannot save files directly to a user's computer (out of security concerns). Unfortunately pointing the main window's URL at your file download means you have little control over what the user experience is when a file ...
Limit file format when using ?
... to know if there is a solution. I'd like to keep solely to HTML and JavaScript; no Flash please.
11 Answers
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How would I create a UIAlertView in Swift?
I have been working to create a UIAlertView in Swift, but for some reason I can't get the statement right because I'm getting this error:
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How can I determine if a JavaScript variable is defined in a page? [duplicate]
How can i check in JavaScript if a variable is defined in a page? Suppose I want to check if a variable named "x" is defined in a page, if I do if(x != null) , it gives me an error.
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jQuery if checkbox is checked
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In CoffeeScript: if $('#my_checkbox').is ':checked'
– Dennis
Feb 21 '14 at 16:53
12
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Pass a PHP array to a JavaScript function [duplicate]
I am trying to get a PHP array variable into a JavaScript variable.
4 Answers
4
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Google Tag Manager 入门指南 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...把如下的脚本放到网站全局的页脚，如：footer.inc：
<script type=”text/javascript”>
var _gaq = _gaq || [];
_gaq.push(["_setAccount", "UA-XXXXXX-1"]);
_gaq.push(["_trackPageview"]);
(function() {
var ga = document.createElement(“script”); ga.type = “text/javasc...
Client on node: Uncaught ReferenceError: require is not defined
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This is because require() does not exist in the browser/client-side JavaScript.
Now you're going to have to make some choices about your client-side JavaScript script management.
You have three options:
Use <script> tag.
Use a CommonJS implementation. Synchronous dependencies like Node....