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Awk学习笔记 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...者姓氏的第一个字母。因为它的作者是三个人，分别是Alfred Aho、Brian Kernighan、Peter Weinberger。gawk是awk的GNU版本，它提供了Bell实验室和GNU的一些扩展。下面介绍的awk是以GUN的gawk为例的，在linux系统中已把awk链接到gawk，所以下面全...
Difference between a Structure and a Union
...ct bar y;
y.a = 3; // OK
y.b = 'c'; // OK
edit: If you're wondering what setting x.b to 'c' changes the value of x.a to, technically speaking it's undefined. On most modern machines a char is 1 byte and an int is 4 bytes, so giving x.b the value 'c' also gives the first byte of x.a that same value...
Function overloading by return type?
Why don't more mainstream statically typed languages support function/method overloading by return type? I can't think of any that do. It seems no less useful or reasonable than supporting overload by parameter type. How come it's so much less popular?
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Read each line of txt file to new array element
...e path & name of your file, eg. ../filename.txt.
Depending how you've set up your text file, you'll have might have to play around with the \n bit.
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Remove characters from C# string
How might I remove characters from a string? For example: "My name @is ,Wan.;'; Wan" .
21 Answers
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print call stack in C or C++
... dump the call stack in a running process in C or C++ every time a certain function is called? What I have in mind is something like this:
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PostgreSQL: Difference between text and varchar (character varying)
What's the difference between the text data type and the character varying ( varchar ) data types?
9 Answers
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Linux command to list all available commands and aliases
Is there a Linux command that will list all available commands and aliases for this terminal session?
20 Answers
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Check free disk space for current partition in bash
...;>$MAILMESSAGE
# sending email (need to have an email client set up or sendmail)
$MAILCMD -s "Urgent MAIL Alert For $(hostname) AWS Server" "$EMAILIDS" < $MAILMESSAGE
[[ -f $MAILMESSAGE ]] && rm -f $MAILMESSAGE
}
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How to group dataframe rows into list in pandas groupby?
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Name: b, dtype: object
In [3]: df1 = df.groupby('a')['b'].apply(list).reset_index(name='new')
df1
Out[3]:
a new
0 A [1, 2]
1 B [5, 5, 4]
2 C [6]
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