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Get MD5 hash of big files in Python
... @EnemyBagJones 'hr' stands for human readable. It returns a string of 32 char length hexadecimal digits: docs.python.org/2/library/md5.html#md5.md5.hexdigest
– Bastien Semene
Mar 27 '18 at 9:46
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Dump a mysql database to a plaintext (CSV) backup from the command line
... separated) files which can import into Excel, etc, quite easily:
% echo 'SELECT * FROM table' | mysql -B -uxxx -pyyy database
Alternatively, if you've got direct access to the server's file system, use SELECT INTO OUTFILE which can generate real CSV files:
SELECT * INTO OUTFILE 'table.csv'
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How can I check whether a option already exist in select by JQuery
How can I check whether a option already exist in select by JQuery?
8 Answers
8
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Hide options in a select list using jQuery
...ave an object with key/value pairs of options I want to hide/remove from a select list.
Neither of the following option selectors work. What am I missing?
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Use JNI instead of JNA to call native code?
...g to the Java standard output:
native "C++" void printHello() {
const char* helloWorld = "Hello, World!";
`System.out.println(#$(helloWorld));`
}
JANET then translates the backtick-embedded Java into the appropriate JNI calls.
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What is a C++ delegate?
...lic:
virtual void Fn( int i )
{
}
};
int main( int /*argc*/, char * /*argv*/ )
{
A a;
CCallback<A> cbk( a, &A::Fn );
cbk.Execute( 3 );
}
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Eclipse git checkout (aka, revert)
...ing" view, right click the deleted file in the "Unstaged Changes" list and select "Replace with HEAD Revision"
– Vlasta Dolejs
Sep 5 '17 at 8:03
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Count table rows
...
SELECT COUNT(*) FROM fooTable;
will count the number of rows in the table.
See the reference manual.
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TSQL Pivot without aggregate function
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yes, but why !!??
Select CustomerID,
Min(Case DBColumnName When 'FirstName' Then Data End) FirstName,
Min(Case DBColumnName When 'MiddleName' Then Data End) MiddleName,
Min(Case DBColumnName When 'LastName' Then Data End) LastNa...
Mysql error 1452 - Cannot add or update a child row: a foreign key constraint fails
... have to get rid of those first.
Here's a query that can find those IDs:
SELECT DISTINCT sourcecode_id FROM
sourcecodes_tags tags LEFT JOIN sourcecodes sc ON tags.sourcecode_id=sc.id
WHERE sc.id IS NULL;
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