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How can I compare two lists in python and return matches
...one, but by far the most obvious way to do it is:
>>> a = [1, 2, 3, 4, 5]
>>> b = [9, 8, 7, 6, 5]
>>> set(a) & set(b)
{5}
if order is significant you can do it with list comprehensions like this:
>>> [i for i, j in zip(a, b) if i == j]
[5]
(only works fo...
What are type lambdas in Scala and what are their benefits?
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Kris NuttycombeKris Nuttycombe
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initializing a boolean array in java
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edited Jan 2 '13 at 16:17
answered Mar 2 '10 at 16:42
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Primary key/foreign Key naming convention [closed]
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Pythonic way of checking if a condition holds for any element of a list
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How to find available versions for a bower dependency
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Is there any WinSCP equivalent for linux? [closed]
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edited Apr 8 '16 at 2:31
answered Nov 18 '08 at 18:44
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How can I output leading zeros in Ruby?
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If the maximum number of digits in the counter is known (e.g., n = 3 for counters 1..876), you can do
str = "file_" + i.to_s.rjust(n, "0")
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Time complexity of Sieve of Eratosthenes algorithm
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Your n/2 + n/3 + n/5 + … n/97 is not O(n), because the number of terms is not constant. [Edit after your edit: O(n2) is too loose an upper bound.] A loose upper-bound is n(1+1/2+1/3+1/4+1/5+1/6+…1/n) (sum of reciprocals of all numbers...
Is having an 'OR' in an INNER JOIN condition a bad idea?
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