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Visual Studio or Resharper functionality for placement of using directives
...o put my using directives inside the current namespace, and not outside as VS and Resharper per default puts them.
7 Answer...
Any reason to write the “private” keyword in C#?
...struct is private. Check here: msdn.microsoft.com/en-us/library/ba0a1yw2(v=vs.90).aspx
– Mitja Bonca
Jul 21 '12 at 10:09
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Test if executable exists in Python?
...he PATHEXT env var because command is as valid as command.com as is script vs script.bat
– Lekensteyn
Dec 2 '11 at 8:47
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Best way to read a large file into a byte array in C#?
... this for a stopgap measure: msdn.microsoft.com/en-us/library/hh285054%28v=vs.110%29.aspx
– Mehrdad Afshari
Mar 13 '13 at 7:18
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Initialize a byte array to a certain value, other than the default null? [duplicate]
... Not sure about it, it might do it implicitly. (I don't have vs2010 running to test it)
– Yochai Timmer
May 27 '11 at 9:19
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Vim: apply settings on files in directory
...s in their .vimrc
The settings can be saved with the other project files (cvs/svn/git/whatever)
It's really easy to have a configuration file per project -- with the plugin, I have a global configuration file for the coding standards of the overall project, and specific configuration files for each ...
How to do constructor chaining in C#
...earching for this. If you are going to work with .NET versions before 4.0 (VS2010), please be advised that you have to create constructor chains as shown above.
However, if you're staying in 4.0, I have good news. You can now have a single constructor with optional arguments! I'll simplify the Foo...
What is the difference between build.sbt and build.scala?
...: http://www.scala-sbt.org/release/docs/Getting-Started/Basic-Def.html#sbt-vs-scala-definition
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Can an ASP.NET MVC controller return an Image?
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VS is telling me that this overload of FileStream() is obsolete.
– MrBoJangles
Jan 23 '12 at 22:36
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What does ||= (or-equals) mean in Ruby?
...(0); h[1] ||= 2. Now consider the two possible expansions h[1] = h[1] || 2 vs h[1] || h[1] = 2. Both expressions evaluate to 0 but the first unnecessarily increases the size of the hash. Perhaps that's why Matz chose to make ||= behave more like the second expansion. (I based this on an example from...