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RESTful Authentication
...c.html HTTP/1.1
Host: www.example.org
Cookie: theme=light; sessionToken=abc123
The cookie technique itself is HTTP-linked, so it's not truly RESTful, which should be protocol-independent, IMHO. It is vulnerable to MiM or Replay attacks.
Granted via Token (OAuth2)
An alternative is to put a token...
“21天教你学会C++” - 创意 - 清泛网 - 专注C/C++及内核技术
...确立了如何发现杰出的软件设计者的三步规划：
尽早系统地识别出最好的设计者群体。
指派一个事业上的导师负责有潜质的对象的发展，小心地帮他保持职业生涯的履历。
让成长中的设计师们有机会互相影响，互相激励。
...
数据挖掘——分词入门 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...就挑选出一个词。目前还没有特别成熟的基于语义的分词系统。
为了让大家快速的了解分词技术，我们采用第一个方式来做测试：基于词典的分词，这种方式简单暴力可以解决百分之七八十的问题。基于词典的分词大概分为以...
Popup弹出菜单扩展 · App Inventor 2 中文网
...的大多数功能已经在上面解释过了。菜单项绑定到简单的操作。
基础使用示例
// 设置锚点组件
when Screen1.Initialize
do
// 设置按钮为锚点
set Popup1.Anchor to Button1
// 从字符串设置菜单项
set Popup1.MenuItems...
Popup弹出菜单扩展 · App Inventor 2 中文网
...的大多数功能已经在上面解释过了。菜单项绑定到简单的操作。
基础使用示例
// 设置锚点组件
when Screen1.Initialize
do
// 设置按钮为锚点
set Popup1.Anchor to Button1
// 从字符串设置菜单项
set Popup1.MenuItems...
How to become an OpenCart guru? [closed]
...y of key => value pairs. As an example
$this->data['example_var'] = 123;
Accessing this in a view is a little should be easy to understand if you're familiar with the extract() method which converts each key into a variable. So the example_var key becomes $example_var and can be accessed as...
Repeat String - Javascript
...sive algorithm (also called "divide and conquer") is on a string of length 123,457. On my FreeBSD computer this algorithm, implemented in the stringFill3() function, creates the string in 0.001058 seconds, while the original stringFill1() function creates the string in 0.0808 seconds. The new functi...
Sublime Text 3能用支持的插件推荐 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...t+P，输Package control就可以选择插件的安装、管理、删除等操作，因为sublime text 3的插件需要基于pyhone 3编写，所以用sublime text 2的安装方法不管用，可以看看我之前写的一篇文章，Sublime text 3如何安装package control办法。
此外，安...
For-each over an array in JavaScript
...
123
Loop backwards
I think the reverse for loop deserves a mention here:
for (var i = array.leng...
How to find list of possible words from a letter matrix [Boggle Solver]
... for letter in word.lower():
if 97 <= ord(letter) < 123:
nextNode = curNode.children[ord(letter) - 97]
if nextNode is None:
nextNode = TrieNode(curNode, letter)
curNode = nextNode
curNode.isWord = True...