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How do I read configuration settings from Symfony2 config.yml?
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parameters:
contact_email: somebody@gmail.com
You should find the call you are making within your controller now works.
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What is the minimum I have to do to create an RPM file?
... of dependencies. It has a config file, /etc/foobar.conf and should be installed in /usr/bin/foobar.
9 Answers
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Passing arguments forward to another javascript function
...manipulate that before passing it along, for example: var copy = [].slice.call(arguments); <remove what you want> myFunc.apply(this, copy);
– Nick Craver♦
Feb 17 '12 at 11:18
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How to make a class JSON serializable
...t;>> magic(f)
'{"fname": "/foo/bar"}'
In that case you can merely call json.dumps(f.__dict__).
If you want more customized output then you will have to subclass JSONEncoder and implement your own custom serialization.
For a trivial example, see below.
>>> from json import JSONE...
JComboBox Selection Change Listener?
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answered Sep 12 '08 at 13:32
jodonnelljodonnell
46.1k1010 gold badges5959 silver badges6565 bronze badges
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Enable Vim Syntax Highlighting By Default
...your $HOME as .vimrc. It switches on a lot of basic stuff for you automatically (syntax, search highlighting, backup etc). You can then tweak it based on your needs.
– oyenamit
Jun 30 '12 at 14:51
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Android: How to put an Enum in a Bundle?
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I use kotlin.
companion object {
enum class Mode {
MODE_REFERENCE,
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Does use of final keyword in Java improve the performance?
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Usually not. For virtual methods, HotSpot keeps track of whether the method has actually been overridden, and is able to perform optimizations such as inlining on the assumption that a method hasn't been overridden - until it lo...
What are some uses of template template parameters?
...alue) {
}
Here, H is a template, but I wanted this function to deal with all specializations of H.
NOTE: I've been programming c++ for many years and have only needed this once. I find that it is a rarely needed feature (of course handy when you need it!).
I've been trying to think of good examp...
What is the exact meaning of IFS=$'\n'?
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Normally bash doesn't interpret escape sequences in string literals. So if you write \n or "\n" or '\n', that's not a linebreak - it's the letter n (in the first case) or a backslash followed by the letter n (in the other two cas...