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Parsing a JSON string in Ruby
...rse JSON, simply use require 'json':
require 'json'
json = JSON.parse '{"foo":"bar", "ping":"pong"}'
puts json['foo'] # prints "bar"
See JSON at Ruby-Doc.
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How to revert a Git Submodule pointer to the commit stored in the containing repository?
...or the key submodule.$name.update
is set to rebase or merge.
Run this and all should be well:
git submodule update --init
You can add the --recursive flag as well to recurse through all submodules.
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What is the difference between Ruby 1.8 and Ruby 1.9
... Sam's slides. The slideshow is less overwhelming to review, but having it all laid out in a list like this is also helpful.
Ruby 1.9 - Major Features
Performance
Threads/Fibers
Encoding/Unicode
gems is (mostly) built-in now
if statements do not introduce scope in Ruby.
What's changed?
Single ...
Add table row in jQuery
...
What if you had a <tbody> and a <tfoot>?
Such as:
<table>
<tbody>
<tr><td>Foo</td></tr>
</tbody>
<tfoot>
<tr><td>footer information</td></tr>
</tf...
Why does C++ need a separate header file?
I've never really understood why C++ needs a separate header file with the same functions as in the .cpp file. It makes creating classes and refactoring them very difficult, and it adds unnecessary files to the project. And then there is the problem with having to include header files, but having to...
Highlight bash/shell code in markdown
...e), then the right identifier to use at the moment is console:
```console
foo@bar:~$ whoami
foo
```
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Convert a list to a string in C#
... separator between the substrings.
var myList = new List<String> { "foo","bar","baz"};
Console.WriteLine(String.Join("-", myList)); // prints "foo-bar-baz"
Depending on your version of .NET you might need to use ToArray() on the list first..
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How to perform element-wise multiplication of two lists?
...
you can multiplication using lambda
foo=[1,2,3,4]
bar=[1,2,5,55]
l=map(lambda x,y:x*y,foo,bar)
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get name of a variable or parameter [duplicate]
... I would include the variable names inside the string, i.e. string.Format("foo={0}, bar={1}", foo, bar), because: in the method they are an implementation detail, but in the file they are part of the document format, which has nothing to do with what the locals are called.
– Ma...
Best way to parse command line arguments in C#? [closed]
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NDesk.options is great, but doesn't seem to really support console apps with more than one distinct command well. If you want that, try ManyConsole which builds on NDesk.Options: nuget.org/List/Packages/ManyConsole
– Frank Schwieterman
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