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Why do Lua arrays(tables) start at 1 instead of 0?
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Although I too found them weird at the beginning, I have learned to love 0-based arrays. But I get by OK with Lua's 1-based arrays, especially by
using Lua's generic for loop and the ipairs operator—I can usually avoid worrying about just how arrays are indexed.
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Intelligent point label placement in R
...ld also note that I think we could all come up with scatterplots with <10-15 points that will be nearly impossible to cleanly label, even by hand, and these will likely break any automatic solution someone comes up with.
Finally, I want to reiterate that I know this isn't the answer you're looki...
How can I easily view the contents of a datatable or dataview in the immediate window
...Set, expand the quick watch, view the Tables, expand that, then view Table[0] (for example). You will see something like {Table1} in the quick watch, but notice that there is also a magnifying glass icon. Click on that icon and your DataTable will open up in a grid view.
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Generate random number between two numbers in JavaScript
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edited Jun 12 '19 at 12:06
Luca Fagioli
9,56333 gold badges4343 silver badges4040 bronze badges
answer...
Java synchronized static methods: lock on object or class
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edited Nov 1 '16 at 8:02
Ravindra babu
39.4k77 gold badges201201 silver badges180180 bronze badges
a...
How can I declare and define multiple variables in one line using C++?
... that if I declare these three variables that they will all have the value 0
10 Answers
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VC DDE（Dynamic Data Exchange）与EXCEL连接 - C/C++ - 清泛网 - 专注C/C++及内核技术
...的通信方案。花了半天时间研究了下，做了个案例，VC6.0下调试通过，很开心。作为一个产品经理，为产品设计搭建好平台，有人的平台，有技术平台，一切目标为了高效的做好产品。
该C++控制台程序案例如下：
// smdata.cpp : ...
How to find the kth smallest element in the union of two sorted arrays?
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You've got it, just keep going! And be careful with the indexes...
To simplify a bit I'll assum...
How to check if BigDecimal variable == 0 in java?
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10 Answers
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How do I find the time difference between two datetime objects in python?
...; difference = later_time - first_time
>>> seconds_in_day = 24 * 60 * 60
datetime.timedelta(0, 8, 562000)
>>> divmod(difference.days * seconds_in_day + difference.seconds, 60)
(0, 8) # 0 minutes, 8 seconds
Subtracting the later time from the first time difference = later_tim...