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How to for each the hashmap? [duplicate]
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I know I'm a bit late for that one, but I'll share what I did too, in case it helps someone else :
HashMap<String, HashMap> selects = new HashMap<String, HashMap>();
for(Map.Entry<String, HashMap> entry : se...
How to format a DateTime in PowerShell
I can format the Get-Date cmdlet no problem like this:
10 Answers
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method of iterating over sqlalchemy model's defined columns?
...f):
return "[%s(%s)]" % (self.__class__.__name__, ', '.join('%s=%s' % (k, self.__dict__[k]) for k in sorted(self.__dict__) if '_sa_' != k[:4]))
It will exclude SA magic attributes, but will not exclude the relations. So basically it might load the dependencies, parents, children etc, which is ...
Remove querystring from URL
...")[0];
}
EDIT
@caub (originally @crl) suggested a simpler combo that works for both query string and hash (though it uses RegExp, in case anyone has a problem with that):
function getPathFromUrl(url) {
return url.split(/[?#]/)[0];
}
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Passing Objects By Reference or Value in C#
...e detail in this. Basically, "pass by reference" doesn't mean what you think it means.
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Is it ever advantageous to use 'goto' in a language that supports loops and functions? If so, why?
...few reasons for using the "goto" statement that I'm aware of (some have spoken to this already):
Cleanly exiting a function
Often in a function, you may allocate resources and need to exit in multiple places. Programmers can simplify their code by putting the resource cleanup code at the end of t...
How do I choose grid and block dimensions for CUDA kernels?
This is a question about how to determine the CUDA grid, block and thread sizes. This is an additional question to the one posted here .
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Generate 'n' unique random numbers within a range [duplicate]
I know how to generate a random number within a range in Python.
4 Answers
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What does the “map” method do in Ruby?
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The map method takes an enumerable object and a block, and runs the block for each element, outputting each returned value from the block (the original object is unchanged unless you use map!):
[1, 2, 3].map { |n| n * n } #=> [1, 4, 9]
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How to convert URL parameters to a JavaScript object?
I have a string like this:
30 Answers
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