大约有 44,000 项符合查询结果（耗时：0.0160秒） [XML]
SQL: capitalize first letter only [duplicate]
...
select replace(wm_concat(new),',','-') exp_res from (select distinct initcap(substr(name,decode(level,1,1,instr(name,'-',1,level-1)+1),decode(level,(length(name)-length(replace(name,'-','')))+1,9999,instr(name,'-',1,level)-1-decode(level,1,0,i...
Inno Setup for Windows service?
...ystem.Environment.UserInteractive)
{
string parameter = string.Concat(args);
switch (parameter)
{
case "--install":
ManagedInstallerClass.InstallHelper(new string[] { Assembly.GetExecutingAssembly().Location });
break;
...
Getting request payload from POST request in Java servlet
... This is interesting, but looks quite inefficient in terms of string concatenation! Any way this can be improved?
– davidfrancis
Aug 15 '16 at 15:47
11
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Merge and interleave two arrays in Ruby
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[ "a", "b" ].concat( ["c", "d"] ) #=> [ "a", "b", "c", "d" ]
– Leo Romanovsky
Oct 4 '12 at 4:41
31
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Join vs. sub-query
...tion level).
Nested sub-queries
SELECT moo, bar
FROM (
SELECT moo, CONCAT(roger, wilco) AS bar
FROM foo
GROUP BY moo
HAVING bar LIKE 'SpaceQ%'
) AS temp_foo
ORDER BY bar
You can nest sub-queries in multiple levels. This can help on huge datasets if you have to group o...
Format number to 2 decimal places
...ect ifnull(format(100.00, 1, 'en_US'), 0)
100.0
Show as Percentage
Select concat(ifnull(format(100.00, 0, 'en_US'), 0), '%')
100%
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Take the content of a list and append it to another list
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Yes, append is for one element, extend is like concat.
– Catalina Chircu
Feb 4 at 6:38
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Is there a way to select sibling nodes?
...s(target) || [],
next = nexSiblings(target) || [];
return prev.concat(next);
}
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The opposite of Intersect()
...nitial, final);
// sum and return the two set.
return setA.Concat(setB);
}
}
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Find the max of two or more columns with pandas
...DataFrame(np.random.randn(5, 1000))
perfplot.show(
setup=lambda n: pd.concat([df_] * n, ignore_index=True),
kernels=[
lambda df: df.assign(new=df.max(axis=1)),
lambda df: df.assign(new=df.values.max(1)),
lambda df: df.assign(new=np.nanmax(df.values, axis=1)),
...