大约有 11,287 项符合查询结果（耗时：0.0162秒） [XML]
What's the meaning of interface{}?
I'm new to interfaces and trying to do SOAP request by github
6 Answers
6
...
How to revert multiple git commits?
...neral rule is that you should not rewrite (change) history that you have published, because somebody might have based their work on it. If you rewrite (change) history, you would make problems with merging their changes and with updating for them.
So the solution is to create a new commit which re...
How to “properly” print a list?
...
In Python 2:
mylist = ['x', 3, 'b']
print '[%s]' % ', '.join(map(str, mylist))
In Python 3 (where print is a builtin function and not a syntax feature anymore):
mylist = ['x', 3, 'b']
print('[%s]' % ', '.join(map(str, mylist)))
Both return:
[x, 3, b]
...
Check if a Class Object is subclass of another Class Object in Java
...e().equals(String.class) . The same applies for other non-derived classes. But how do I check derived classes? E.g. LinkedList as subclass of List . I can't find any isSubclassOf(...) or extends(...) method. Do I need to walk through all getSuperClass() and find my supeclass by my own?
...
How do I get the row count of a pandas DataFrame?
I'm trying to get the number of rows of dataframe df with Pandas, and here is my code.
14 Answers
...
Matrix Transpose in Python
I am trying to create a matrix transpose function for python but I can't seem to make it work.
Say I have
18 Answers
...
Get a specific bit from byte
I have a byte, specifically one byte from a byte array which came in via UDP sent from another device. This byte stores the on/off state of 8 relays in the device.
...
How do I compare strings in Java?
I've been using the == operator in my program to compare all my strings so far.
However, I ran into a bug, changed one of them into .equals() instead, and it fixed the bug.
...
Fastest way to check if a value exists in a list
...a
Clearest and fastest way to do it.
You can also consider using a set, but constructing that set from your list may take more time than faster membership testing will save. The only way to be certain is to benchmark well. (this also depends on what operations you require)
...
How to convert a string with comma-delimited items to a list in Python?
...
Like this:
>>> text = 'a,b,c'
>>> text = text.split(',')
>>> text
[ 'a', 'b', 'c' ]
Alternatively, you can use eval() if you trust the string to be safe:
>>> text = 'a,b,c'
>>> text = eval('[' + text + ']')
...