大约有 18,339 项符合查询结果(耗时:0.0258秒) [XML]
How to get cumulative sum
...
select t1.id, t1.SomeNumt, SUM(t2.SomeNumt) as sum
from @t t1
inner join @t t2 on t1.id >= t2.id
group by t1.id, t1.SomeNumt
order by t1.id
SQL Fiddle example
Output
| ID | SOMENUMT | SUM |
-----------------------
| 1 | 1...
Efficiently convert rows to columns in sql server
... from yourtable
group by ColumnName, id
order by id
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = N'SELECT ' + @cols + N' from
(
select value, Column...
How do I find a “gap” in running counter with SQL?
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In MySQL and PostgreSQL:
SELECT id + 1
FROM mytable mo
WHERE NOT EXISTS
(
SELECT NULL
FROM mytable mi
WHERE mi.id = mo.id + 1
)
ORDER BY
id
LIMIT 1
In SQL Server:
SELECT TOP 1
id + 1
FR...
Does MongoDB's $in clause guarantee order
...y have two options.
So let's say that you were matching on the values of _id in your documents with an array that is going to be passed in to the $in as [ 4, 2, 8 ].
Approach using Aggregate
var list = [ 4, 2, 8 ];
db.collection.aggregate([
// Match the selected documents by "_id"
{...
get an element's id
Is there another way to get an DOM element's ID?
8 Answers
8
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Can multiple different HTML elements have the same ID if they're different elements?
Can multiple HTML elements have the same ID if they're of different element types? Is a scenario like this valid? Eg:
16 An...
How to specify id when uses include in layout xml file
...ml file, I have included other layout xml file (each
with a different android id).
11 Answers
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MySQL INNER JOIN select only one row from second table
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You need to have a subquery to get their latest date per user ID.
SELECT a.*, c.*
FROM users a
INNER JOIN payments c
ON a.id = c.user_ID
INNER JOIN
(
SELECT user_ID, MAX(date) maxDate
FROM payments
GROUP BY user_ID
) b ON c.user_ID = b....
jQuery Selector: Id Ends With?
Is there a selector that I can query for elements with an ID that ends with a given string?
9 Answers
...
Select first row in each GROUP BY group?
... Firebird 3.0+, Teradata, Sybase, Vertica:
WITH summary AS (
SELECT p.id,
p.customer,
p.total,
ROW_NUMBER() OVER(PARTITION BY p.customer
ORDER BY p.total DESC) AS rk
FROM PURCHASES p)
SELECT s.*
FROM summary s
WHERE ...