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Linear Regression and group by in R
...ual time series with one field for year (22 years) and another for state (50 states). I want to fit a regression for each state so that at the end I have a vector of lm responses. I can imagine doing for loop for each state then doing the regression inside the loop and adding the results of each reg...
Are list-comprehensions and functional functions faster than “for loops”?
...el loop:
>>> dis.dis(<the code object for `[x for x in range(10)]`>)
1 0 BUILD_LIST 0
3 LOAD_FAST 0 (.0)
>> 6 FOR_ITER 12 (to 21)
9 STORE_FAST 1 (x)
12 LOAD_FAST...
How to change the order of DataFrame columns?
...ged as needed.
This is what you have now:
In [6]: df
Out[6]:
0 1 2 3 4 mean
0 0.445598 0.173835 0.343415 0.682252 0.582616 0.445543
1 0.881592 0.696942 0.702232 0.696724 0.373551 0.670208
2 0.662527 0.955193 0.131016 0.609548 0.8046...
How to use a decimal range() step value?
Is there a way to step between 0 and 1 by 0.1?
33 Answers
33
...
How can I profile C++ code running on Linux?
...
1440
If your goal is to use a profiler, use one of the suggested ones.
However, if you're in a hurry...
How does the Brainfuck Hello World actually work?
...
+100
1. Basics
To understand Brainfuck you must imagine infinite array of cells initialized by 0 each.
...[0][0][0][0][0]...
When brai...
What is the easiest way to remove the first character from a string?
...
I kind of favor using something like:
asdf = "[12,23,987,43"
asdf[0] = ''
p asdf
# >> "12,23,987,43"
I'm always looking for the fastest and most readable way of doing things:
require 'benchmark'
N = 1_000_000
puts RUBY_VERSION
STR = "[12,23,987,43"
Benchmark.bm(7) do |b|
...
Is there a simple way to remove multiple spaces in a string?
...
Francisco Couzo
8,04633 gold badges2929 silver badges3737 bronze badges
answered Oct 9 '09 at 21:52
Josh LeeJosh Lee
...
Convert floats to ints in Pandas?
...nge(5), columns=['a'])
df.a = df.a.astype(float)
df
Out[33]:
a
0 0.0000000
1 1.0000000
2 2.0000000
3 3.0000000
4 4.0000000
pd.options.display.float_format = '{:,.0f}'.format
df
Out[35]:
a
0 0
1 1
2 2
3 3
4 4
...
Convert tuple to list and back
...confused.
– Jimmy
Aug 28 '18 at 19:30
6
...