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Factors in R: more than an annoyance?
... my experience factors are basically a pain and I never use them. I always convert to characters. I feel oddly like I'm missing something.
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Write to UTF-8 file in Python
...e help? I need to append a string (paragraph) to a text file. Do I need to convert that into an integer first before writing?
– Mugen
Apr 2 '18 at 12:40
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error C2440: “初始化”: 无法从“const int”转换为“int &” - C/C++ - ...
error C2440: “初始化”: 无法从“const int”转换为“int &”error C2440: 初始化: 无法从const int转换为int &转换丢失限定符。#include <iostream> int main() { const int...error C2440: “初始化”: 无法从“const int”转换为“int &”
转换丢失限定...
How do I sort a vector of pairs based on the second element of the pair?
...t to std::sort)
struct sort_pred {
bool operator()(const std::pair<int,int> &left, const std::pair<int,int> &right) {
return left.second < right.second;
}
};
std::sort(v.begin(), v.end(), sort_pred());
If you're using a C++11 compiler, you can write the sam...
What is the difference between a definition and a declaration?
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A declaration introduces an identifier and describes its type, be it a type, object, or function. A declaration is what the compiler needs to accept references to that identifier. These are declarations:
extern int bar;
extern int g(int,...
How does collections.defaultdict work?
...and type objects). For the first example, default items are created using int(), which will return the integer object 0. For the second example, default items are created using list(), which returns a new empty list object.
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In c# is there a method to find the max of 3 numbers?
Like Math.Max but takes 3 or params of int?
10 Answers
10
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Java, Simplified check if int array contains int
...at I could make my code shorter by using a different way of checking if an int array contains an int, although he won't tell me what it is :P.
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Printing Java Collections Nicely (toString Doesn't Return Pretty Output)
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You could convert it to an array and then print that out with Arrays.toString(Object[]):
System.out.println(Arrays.toString(stack.toArray()));
share
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C++: Rounding up to the nearest multiple of a number
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This works for positive numbers, not sure about negative. It only uses integer math.
int roundUp(int numToRound, int multiple)
{
if (multiple == 0)
return numToRound;
int remainder = numToRound % multiple;
if (remainder == 0)
return numToRound;
return numToRoun...