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Ruby Hash to array of values
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answered Mar 5 '12 at 0:48
Ray ToalRay Toal
76.4k1212 gold badges143143 silver badges204204 bronze badges
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python re.sub group: number after \number
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330
The answer is:
re.sub(r'(foo)', r'\g<1>123', 'foobar')
Relevant excerpt from the docs:
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Calling clojure from java
...intln (str "(binomial 5 3): " (binomial 5 3)))
(println (str "(binomial 10042 111): " (binomial 10042 111)))
)
If you run it, you should see something like:
(binomial 5 3): 10
(binomial 10042 111): 49068389575068144946633777...
And here's a Java program that calls the -binomial function in th...
overlay two images in android to set an imageview
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Resources r = getResources();
Drawable[] layers = new Drawable[2];
layers[0] = r.getDrawable(R.drawable.t);
layers[1] = r.getDrawable(R.drawable.tt);
LayerDrawable layerDrawable = new LayerDrawable(layers);
testimage.setImageDrawable(layerDrawable);
(I haven't tested this code so there may be a m...
Stubbing a class method with Sinon.js
...ensor.prototype.
sinon.stub(Sensor, "sample_pressure", function() {return 0})
is essentially the same as this:
Sensor["sample_pressure"] = function() {return 0};
but it is smart enough to see that Sensor["sample_pressure"] doesn't exist.
So what you would want to do is something like these:
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How do you add an array to another array in Ruby and not end up with a multi-dimensional result?
...note the asterisk, and that a2 is the receiver
or splice:
a1[a1.length, 0] = a2
a1[a1.length..0] = a2
a1.insert(a1.length, *a2)
or append and flatten:
(a1 << a2).flatten! # a call to #flatten instead would return a new array
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How to delete multiple values from a vector?
I have a vector like: a = c(1:10) and I need to remove multiple values, like: 2, 3, 5
8 Answers
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Array.Copy vs Buffer.BlockCopy
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edited Feb 15 '17 at 12:09
Ajay
16.3k99 gold badges4646 silver badges9090 bronze badges
answered Sep 7...
How to check if field is null or empty in MySQL?
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edited Mar 30 '18 at 5:18
answered Jul 24 '13 at 11:39
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c++提取复数的实部和虚部 - C/C++ - 清泛网 - 专注C/C++及内核技术
...arse(COMPLEX * cp, const char * strCplx, const int len)
{
memset(cp, 0, sizeof(COMPLEX));
char buf[MAX_BUF_LEN];
int signPos = -1, // +/-号位置
iPos = -1; // 结尾的i的位置
for (int i = len-1; i >-1; i--)
{
if ('i' == strCplx[i])
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