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How to create a drop shadow only on one side of an element?
...ent is required.
#box {
background-color: #3D6AA2;
width: 160px;
height: 90px;
position: absolute;
top: calc(10% - 10px);
left: calc(50% - 80px);
}
.box-shadow:after {
content:"";
position:absolute;
width:100%;
bottom:1px;
z-index:-1;
...
Reset/remove CSS styles for element only
...initial values:
.reset-this {
animation : none;
animation-delay : 0;
animation-direction : normal;
animation-duration : 0;
animation-fill-mode : none;
animation-iteration-count : 1;
animation-name : none;
animation-play-state : running;
animation-timing-function ...
Remove duplicate values from JS array [duplicate]
... |
edited Dec 26 '16 at 10:53
Martijn Pieters♦
839k212212 gold badges32183218 silver badges28092809 bronze badges
...
WPF ToolBar: how to remove grip and overflow
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answered Jun 26 '09 at 20:57
rmoorermoore
14.2k44 gold badges5656 silver badges5959 bronze badges
...
jquery if div id has children
...
if ( $('#myfav').children().length > 0 ) {
// do something
}
This should work. The children() function returns a JQuery object that contains the children. So you just need to check the size and see if it has at least one child.
...
Checking for the correct number of arguments
...
#!/bin/sh
if [ "$#" -ne 1 ] || ! [ -d "$1" ]; then
echo "Usage: $0 DIRECTORY" >&2
exit 1
fi
Translation: If number of arguments is not (numerically) equal to 1 or the first argument is not a directory, output usage to stderr and exit with a failure status code.
More friendly er...
Java 8 forEach with index [duplicate]
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170
Since you are iterating over an indexable collection (lists, etc.), I presume that you can then ...
Checking to see if one array's elements are in another array in PHP
...
205
You can use array_intersect().
$result = !empty(array_intersect($people, $criminals));
...
Get the name of the currently executing method
$0 is the variable for the top level Ruby program, but is there one for the current method?
5 Answers
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How to use > in an xargs command?
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201
Do not make the mistake of doing this:
sh -c "grep ABC {} > {}.out"
This will break under...
