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How to create a drop shadow only on one side of an element?

...ent is required. #box { background-color: #3D6AA2; width: 160px; height: 90px; position: absolute; top: calc(10% - 10px); left: calc(50% - 80px); } .box-shadow:after { content:""; position:absolute; width:100%; bottom:1px; z-index:-1; ...
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Reset/remove CSS styles for element only

...initial values: .reset-this { animation : none; animation-delay : 0; animation-direction : normal; animation-duration : 0; animation-fill-mode : none; animation-iteration-count : 1; animation-name : none; animation-play-state : running; animation-timing-function ...
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Remove duplicate values from JS array [duplicate]

... | edited Dec 26 '16 at 10:53 Martijn Pieters♦ 839k212212 gold badges32183218 silver badges28092809 bronze badges ...
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WPF ToolBar: how to remove grip and overflow

... answered Jun 26 '09 at 20:57 rmoorermoore 14.2k44 gold badges5656 silver badges5959 bronze badges ...
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jquery if div id has children

... if ( $('#myfav').children().length > 0 ) { // do something } This should work. The children() function returns a JQuery object that contains the children. So you just need to check the size and see if it has at least one child. ...
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Checking for the correct number of arguments

... #!/bin/sh if [ "$#" -ne 1 ] || ! [ -d "$1" ]; then echo "Usage: $0 DIRECTORY" >&2 exit 1 fi Translation: If number of arguments is not (numerically) equal to 1 or the first argument is not a directory, output usage to stderr and exit with a failure status code. More friendly er...
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Java 8 forEach with index [duplicate]

... 170 Since you are iterating over an indexable collection (lists, etc.), I presume that you can then ...
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Checking to see if one array's elements are in another array in PHP

... 205 You can use array_intersect(). $result = !empty(array_intersect($people, $criminals)); ...
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Get the name of the currently executing method

$0 is the variable for the top level Ruby program, but is there one for the current method? 5 Answers ...
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How to use > in an xargs command?

... 201 Do not make the mistake of doing this: sh -c "grep ABC {} > {}.out" This will break under...