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Java EE web development, where do I start and what skills do I need? [closed]
... all, "Java EE" has since Sep 2019 been renamed to "Jakarta EE", starting with version 8. Historically, there was also the term "J2EE" which covered versions 1.2 until 1.4. The "Java EE" covered versions 5 until 8. See also Java Platform, Enterprise Edition, History on Wikipedia.
What exactly do I ...
Android SDK installation doesn't find JDK
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Press Back when you get the notification and then Next. This time it will find the JDK.
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Serializing to JSON in jQuery [duplicate]
...ing to object, use JSON.parse:
var your_object = JSON.parse(json_text);
It was recently recommended by John Resig:
...PLEASE start migrating
your JSON-using applications over to
Crockford's json2.js. It is fully
compatible with the ECMAScript 5
specification and gracefully degrades
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Vertically align text next to an image?
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Actually, in this case it's quite simple: apply the vertical align to the image. Since it's all in one line, it's really the image you want aligned, not the text.
<!-- moved "vertical-align:middle" style from span to img -->
<div>...
C++ static virtual members?
Is it possible in C++ to have a member function that is both static and virtual ? Apparently, there isn't a straightforward way to do it ( static virtual member(); is a compile error), but is there at least a way to achieve the same effect?
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JavaScript dependency management: npm vs. bower vs. volo [closed]
...bower. Here is an expansive article on npm and bower (does not cover volo) it goes into plenty of detail.
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Maintain the aspect ratio of a div with CSS
I want to create a div that can change its width/height as the window's width changes.
27 Answers
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Executing JavaScript without a browser?
I am looking into Javascript programming without a browser. I want to run scripts from the Linux or Mac OS X command line, much like we run any other scripting language (ruby, php, perl, python...)
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Are negative array indexes allowed in C?
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That is correct. From C99 §6.5.2.1/2:
The definition of the subscript
operator [] is that E1[E2] is
identical to (*((E1)+(E2))).
There's no magic. It's a 1-1 equivalence. As always when dereferencing a pointer (*), you need to be sure it's pointing to a valid addr...
Your project contains error(s), please fix it before running it
I am developing a simple Android application. But when I run Eclipse, it shows the following error:
26 Answers
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