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How can I create Min stl priority_queue?
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Use std::greater as the comparison function:
std::priority_queue<int, std::vector<int>, std::greater<int> > my_min_heap;
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Setting an int to Infinity in C++
I have an int a that needs to be equal to "infinity". This means that if
6 Answers
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How to make inline functions in C#
...ral syntaxes available.
Anonymous methods were added in C# 2.0:
Func<int, int, int> add = delegate(int x, int y)
{
return x + y;
};
Action<int> print = delegate(int x)
{
Console.WriteLine(x);
}
Action<int> helloWorld = delegate // parameters can be elided if ignored
{
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Why would I make() or new()?
The introduction documents dedicate many paragraphs to explaining the difference between new() and make() , but in practice, you can create objects within local scope and return them.
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Programmatically set left drawable in a TextView
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You can use setCompoundDrawablesWithIntrinsicBounds(int left, int top, int right, int bottom)
set 0 where you don't want images
Example for Drawable on the left:
TextView textView = (TextView) findViewById(R.id.myTxtView);
textView.setCompoundDrawablesWithIntri...
java.util.Date vs java.sql.Date
...What I am saying that save the milliseconds/nanoseconds as plain longs and convert them to whatever objects you are using (obligatory joda-time plug). One hacky way which can be done is to store the date component as one long and time component as another, for example right now would be 20100221 and...
Why is the asterisk before the variable name, rather than after the type?
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They are EXACTLY equivalent.
However, in
int *myVariable, myVariable2;
It seems obvious that myVariable has type int*, while myVariable2 has type int.
In
int* myVariable, myVariable2;
it may seem obvious that both are of type int*, but that is not correct as my...
Initializing a two dimensional std::vector
...ccepts an initial size and a default value:
std::vector<std::vector<int> > fog(
A_NUMBER,
std::vector<int>(OTHER_NUMBER)); // Defaults to zero initial value
If a value other than zero, say 4 for example, was required to be the default then:
std::vector<std::vector<...
Can I call a base class's virtual function if I'm overriding it?
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The C++ syntax is like this:
class Bar : public Foo {
// ...
void printStuff() {
Foo::printStuff(); // calls base class' function
}
};
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'const int' vs. 'int const' as function parameters in C++ and C
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const T and T const are identical. With pointer types it becomes more complicated:
const char* is a pointer to a constant char
char const* is a pointer to a constant char
char* const is a constant pointer to a (mutable) char
In other words, (1) and (2) are identi...