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Explain the encapsulated anonymous function syntax
...on () {
alert(2 + 2);
}());
Or named function expression:
(function foo() {
alert(2 + 2);
}());
The Parentheses (formally called the Grouping Operator) can surround only expressions, and a function expression is evaluated.
The two grammar productions can be ambiguous, and they can look...
java: HashMap not working
...ittle difference in the code. Auto-boxing means you can write:
myMap.put("foo", 3);
instead of:
myMap.put("foo", new Integer(3));
Auto-boxing means the first version is implicitly converted to the second. Auto-unboxing means you can write:
int i = myMap.get("foo");
instead of:
int i = myMa...
Creating an empty file in Ruby: “touch” equivalent?
...
If you are worried about file handles:
File.open("foo.txt", "w") {}
From the docs:
If the optional code block is given, it will be passed the opened file
as an argument, and the File object will automatically be closed when
the block terminates.
...
What's the use of do while(0) when we define a macro? [duplicate]
...up several statements into one macro.
Assume you did something like:
if (foo)
INIT_LIST_HEAD(bar);
If the macro was defined without the encapsulating do { ... } while (0);, the above code would expand to
if (foo)
(bar)->next = (bar);
(bar)->prev = (bar);
This is clearly not...
How to split (chunk) a Ruby array into parts of X elements? [duplicate]
...
Take a look at Enumerable#each_slice:
foo.each_slice(3).to_a
#=> [["1", "2", "3"], ["4", "5", "6"], ["7", "8", "9"], ["10"]]
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Difference between parameter and argument [duplicate]
...d actual parameter etc.
So here, x and y would be formal parameters:
int foo(int x, int y) {
...
}
Whereas here, in the function call, 5 and z are the actual arguments:
foo(5, z);
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How to clear ostringstream [duplicate]
...his method? For example, for (int i=0; i<100; ++i) { std::ostringstream foo; foo << "bar"; std::cout << foo.str() << " ";}. Will this print: bar bar bar [...] or bar barbar barbarbar [...]?
– Thanasis Papoutsidakis
Nov 2 '13 at 15:42
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jQuery dot in ID selector? [duplicate]
... escaped with with two backslashes: \\. For example, an element with
id="foo.bar", can use the selector $("#foo\\.bar").
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Using a string variable as a variable name [duplicate]
...
You can use exec for that:
>>> foo = "bar"
>>> exec(foo + " = 'something else'")
>>> print bar
something else
>>>
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imp...
Swift equivalent of [NSBundle bundleForClass:[self class]]
... class inside your value type. Example of the latter solution: Bundle(for: Foo.Bar.self) where Foo - your struct, Bar - some inner class.
– Vadim Bulavin
Apr 24 '17 at 13:37
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