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How to check if object has any properties in JavaScript?

... | edited Dec 4 '18 at 3:39 Reese Jones 6855 bronze badges answered Apr 20 '10 at 6:49 ...
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Order data frame rows according to vector with specific order

... 236 Try match: df <- data.frame(name=letters[1:4], value=c(rep(TRUE, 2), rep(FALSE, 2))) target...
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Postgres: Distinct but only for one column

... (having more than 1 mio. rows), but I have also many duplicates. I select 3 fields: id , name , metadata . 3 Answers ...
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How to list the contents of a package using YUM?

... 438 There is a package called yum-utils that builds on YUM and contains a tool called repoquery tha...
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Is there any way to ignore INSTALL_FAILED_VERSION_DOWNGRADE on application install with the Android

... answered Dec 7 '12 at 23:25 supereeesupereee 3,03511 gold badge1111 silver badges99 bronze badges ...
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How does type Dynamic work and how to use it?

...> val d = new DynImpl d: DynImpl = DynImpl@6040af64 scala> d.foo res37: String = foo scala> d.bar res38: String = bar scala> d.selectDynamic("foo") res54: String = foo As one can see, it is also possible to call the dynamic methods explicitly. updateDynamic Because updateDynamic i...
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Why is git prompting me for a post-pull merge commit message?

... 3 Answers 3 Active ...
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Using querySelector with IDs that are numbers

...Unicode code point. For example, the code point for the character 1 is U+0031, so you would escape it as \000031 or \31 . Basically, to escape any numeric character, just prefix it with \3 and append a space character ( ). Yay Unicode! So your code would end up as (CSS first, JS second): #\3...
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UnicodeDecodeError: 'ascii' codec can't decode byte 0xd1 in position 2: ordinal not in range(128)

... 153 Unicode is not equal to UTF-8. The latter is just an encoding for the former. You are doing it ...
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(Deep) copying an array using jQuery [duplicate]

...pying, it is not suitable for multidimensional arrays: var a =[[1], [2], [3]]; var b = a.slice(); b.shift().shift(); // a is now [[], [2], [3]] Note that although I've used shift().shift() above, the point is just that b[0][0] contains a pointer to a[0][0] rather than a value. Likewise delete...