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using jquery $.ajax to call a PHP function
This may be a simple answer, but I'm using jQuery's $.ajax to call a PHP script. What I want to do is basically put that PHP script inside a function and call the PHP function from javascript.
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XAMPP - Port 80 in use by “Unable to open process” with PID 4! 12
...RVER)" also uses port 80 and so it should be stopped if MS-SQL sever is insalled on your machine.
– johnkarka
Nov 21 '15 at 12:01
1
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Create an index on a huge MySQL production table without table locking
...d or dropped. The CREATE INDEX or DROP INDEX statement only finishes after all transactions that are accessing the table are completed, so that the initial state of the index reflects the most recent contents of the table. Previously, modifying the table while an index is being created or dropped ty...
How to fix “Attempted relative import in non-package” even with __init__.py
...ry to execute the above shell command, the fact that you need __init__.pys all the way down, and the __package__-modifying trickery (described below by BrenBarn) needed to allow these imports for executable scripts (e.g. when using a shebang and doing ./my_script.py at the Unix shell) would all be u...
How to import other Python files?
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importlib was added to Python 3 to programmatically import a module.
It is just a wrapper around __import__, see the docs.
import importlib
moduleName = input('Enter module name:')
importlib.import_module(moduleName)
Note: the .py extension should be removed from mod...
Program only crashes as release build — how to debug?
I've got a "Schroedinger's Cat" type of problem here -- my program (actually the test suite for my program, but a program nonetheless) is crashing, but only when built in release mode, and only when launched from the command line. Through caveman debugging (ie, nasty printf() messages all over the ...
Define css class in django Forms
... The only sane solution, I must say. Thank you!. Python code, and especially in form's definition, is the last place to put stuff for styling - these definitely belong to the templates.
– Boris Chervenkov
Nov 12 '11 at 23:09
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“No such file or directory” error when executing a binary
I was installing a binary Linux application on Ubuntu 9.10 x86_64. The app shipped with an old version of gzip (1.2.4), that was compiled for a much older kernel:
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How to pass parameters to a view
....options:
initialize: function(options) {
this.options = options;
_.bindAll(this, 'render');
},
or use some finer ways as described by @Brave Dave.
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PHP & mySQL: Year 2038 Bug: What is it? How to solve it?
.... Instead of asking my question in bulk, I preferred to break it up into small parts so that it is easy for novice users to understand as well. So my question(s):
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