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python design patterns [closed]
...for their existence.
It's nothing more than
class Null(object):
def __init__(self, *args, **kwargs):
"Ignore parameters."
return None
def __call__(self, *args, **kwargs):
"Ignore method calls."
return self
def __getattr__(self, mname):
"Ignore...
How to quickly check if folder is empty (.NET)?
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There is a new feature in Directory and DirectoryInfo in .NET 4 that allows them to return an IEnumerable instead of an array, and start returning results before reading all the directory contents.
What's New in the BCL in .NET 4 Beta 1
Directory.EnumerateFileSystemEntries method overloads
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Java “lambda expressions not supported at this language level”
...: android { compileOptions { sourceCompatibility JavaVersion.VERSION_1_8 targetCompatibility JavaVersion.VERSION_1_8 } }
– BaDo
Sep 25 '15 at 2:30
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How to implement a ConfigurationSection with a ConfigurationElementCollection
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The previous answer is correct but I'll give you all the code as well.
Your app.config should look like this:
<?xml version="1.0" encoding="utf-8" ?>
<configuration>
<configSections>
<section name="ServicesSection" type="RT.Core.Config.Servic...
How do I print the full value of a long string in gdb?
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As long as your program's in a sane state, you can also call (void)puts(your_string) to print it to stdout. Same principle applies to all functions available to the debugger, actually.
share
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Insert, on duplicate update in PostgreSQL?
...it would be much slower, because each upsert would be its' own individual call into the database.
– baash05
Mar 1 '12 at 0:27
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Load multiple packages at once
...t retyping the require command over and over? I've tried three approaches all of which crash and burn.
10 Answers
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What is the difference between __dirname and ./ in node.js?
...ere in relation to your current directory, is there any reason to use the __dirname variable instead of just a regular ./ ? I've been using ./ thus far in my code and just discovered the existence of __dirname , and essentially want to know whether it would be smart to convert my ./'s to that, a...
Check if a value is within a range of numbers
...u're asking a question about numeric comparisons, so regular expressions really have nothing to do with the issue. You don't need "multiple if" statements to do it, either:
if (x >= 0.001 && x <= 0.009) {
// something
}
You could write yourself a "between()" function:
function b...
Removing multiple keys from a dictionary safely
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Why not like this:
entries = ('a', 'b', 'c')
the_dict = {'b': 'foo'}
def entries_to_remove(entries, the_dict):
for key in entries:
if key in the_dict:
del the_dict[key]
A more compact version was provided by mattbornski using dict.pop()
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