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Passing a URL with brackets to curl
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edited Jul 2 '19 at 20:14
moveson
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answered Nov...
How do you downgrade rubygems?
I have rubygems 1.3.1 installed but I want to go back to 1.2.0. What's the command to downgrade rubygems?
6 Answers
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Count cells that contain any text
...ot empty/blank, count it. I believe this is what you want.
=COUNTIF(A1:A10, "<>")
Otherwise you can use CountA as Scott suggests
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How much size “Null” value takes in SQL Server
I have a large table with say 10 columns. 4 of them remains null most of the times. I have a query that does null value takes any size or no size in bytes. I read few articles some of them are saying :
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Error:(1, 0) Plugin with id 'com.android.application' not found
This is my first attempt at Android Studio. I installed 0.8.0 and updated to 0.8.2. As soon as a project is created I get the error message:
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ActiveRecord: size vs count
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edited Jul 10 '12 at 22:15
Jo Liss
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Visual Studio or Resharper functionality for placement of using directives
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UPDATE - ReSharper 2016.1: This option is now moved to Code Editing → C# → Code Style → Add 'using' directive to the deepest scope
Have you tried the ReSharper option:
Languages → C# → Formatting Style → Namespace Imports → Add u...
What's the meaning of * (asterisk) in XAML ColumnDefinition?
...s definition
<Grid.ColumnDefinitions>
<ColumnDefinition Width="0.07*"/>
<ColumnDefinition Width="0.93*"/>
</Grid.ColumnDefinitions>
The first column will get 7% of the total space available and the second column would get 93%. On the other hand if you had this definiti...
How do I decode a string with escaped unicode?
...ouble searching for it. How can I decode a string with unicode from http\u00253A\u00252F\u00252Fexample.com to http://example.com with JavaScript? I tried unescape , decodeURI , and decodeURIComponent so I guess the only thing left is string replace.
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Difference between variable declaration syntaxes in Javascript (including global variables)?
...al terms they're not usually big ones.
There's a fourth way, and as of ES2015 (ES6) there's two more. I've added the fourth way at the end, but inserted the ES2015 ways after #1 (you'll see why), so we have:
var a = 0; // 1
let a = 0; // 1.1 (new with ES2015)
const a = 0; // 1.2 (new wit...
