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How to split a string and assign it to variables

In Python it is possible to split a string and assign it to variables: 9 Answers 9 ...
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“tag already exists in the remote" error after recreating the git tag

...o get everyone who already has the "wrong" tag to delete their "wrong tag" and replace it with the new "right tag". Testing in Git 2.10/2.11 shows that retaining the old tag is the default behavior for clients running git fetch, and updating is the default behavior for clients running git fetch --t...
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Return a value if no rows are found in Microsoft tSQL

...1) > 0 THEN 1 ELSE 0 END AS [Value] FROM Sites S WHERE S.Id = @SiteId and S.Status = 1 AND (S.WebUserId = @WebUserId OR S.AllowUploads = 1) share | improve this answer | ...
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What is the difference between exit(0) and exit(1) in C?

Can anyone tell me? What is the difference between exit(0) and exit(1) in C language? 11 Answers ...
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What is the “right” way to iterate through an array in Ruby?

...arts, is pretty good on this count. There's no difference between an array and a hash (maybe I'm naive, but this seems obviously right to me), and to iterate through either you just do ...
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What's the difference between “mod” and “remainder”?

My friend said that there are differences between "mod" and "remainder". 5 Answers 5 ...
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How to calculate date difference in JavaScript?

... milliseconds to years. You must be aware of bissextile year, of timezone, and some days have 23 or 25 hours. Some years have 365,25 days, so there is no simple arithmetic here (still looking for an accurate solution). – Alexandre Salomé May 20 '14 at 12:50 ...
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Convert light frequency to RGB?

... And the Fourmilab article makes the important point that some colours are not representable in RGB (bright oranges being a good example) because you cannot "make" arbitrary colours of light by adding three primary colours tog...
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~x + ~y == ~(x + y) is always false?

... Assume for the sake of contradiction that there exists some x and some y (mod 2n) such that ~(x+y) == ~x + ~y By two's complement*, we know that, -x == ~x + 1 <==> -1 == ~x + x Noting this result, we have, ~(x+y) == ~x + ~y <==> ~(x+y) + (x+y) == ~x + ~y...
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What does |= (ior) do in Python?

.... See examples below. Sets For example, the union of two assigned sets s1 and s2 share the following equivalent expressions: >>> s1 = s1 | s12 # 1 >>> s1 |= s2 # 2 >>> s1.__ior__(s2) ...