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SQL - using alias in Group By
...ceptions though: MySQL and Postgres seem to have additional smartness that allows it.
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Fast Linux File Count for a large number of files
...ke a while if there are a lot of them. Also there will be no output until all of the names are read and sorted. Use the ls -f option to turn off sorting.
ls -f | wc -l
Note that this will also enable -a, so ., .., and other files starting with . will be counted.
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How to determine height of UICollectionView with FlowLayout
...y question: I was completely searching in the wrong place, digging through all the documentation I could find on UICollectionView.
The simple and easy solution lies in the underlying layout: Just call collectionViewContentSize on your myCollectionView.collectionViewLayout property and you get the h...
Routes with Dash `-` Instead of Underscore `_` in Ruby on Rails
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there has to be a better and faster way to convert all routes that has undersore to hyphens
– carbonr
Mar 31 '13 at 17:59
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How to get RelativeLayout working with merge and include?
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This is really easier, less hardcoded, and more optimized solution than packing <include/> into another layout. Think what would you do if you would work with lists.
– teoREtik
Feb 2 '12 at ...
C# Lazy Loaded Automatic Properties
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JaredParJaredPar
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Deserialize JSON with C#
I'm trying to deserialize a Facebook friend's Graph API call into a list of objects. The JSON object looks like:
10 Answ...
Simulate CREATE DATABASE IF NOT EXISTS for PostgreSQL?
...an work around it from within psql by executing the DDL statement conditionally:
SELECT 'CREATE DATABASE mydb'
WHERE NOT EXISTS (SELECT FROM pg_database WHERE datname = 'mydb')\gexec
The manual:
\gexec
Sends the current query buffer to the server, then treats each column of each row of the query's...
How do you convert a byte array to a hexadecimal string, and vice versa?
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You're using SubString. Doesn't this loop allocate a horrible amount of string objects?
– Wim Coenen
Mar 6 '09 at 16:36
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Is there a performance difference between i++ and ++i in C++?
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However, if i is an instance of a C++ class, then i++ and ++i are making calls to one of the operator++ functions. Here's a standard pair of these functions:
Foo& Foo::operator++() // called for ++i
{
this->data += 1;
return *this;
}
Foo Foo::operator++(int ignored_dummy_value) ...