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Wait for a process to finish

... +50 To wait for any process to finish Linux: tail --pid=$pid -f /dev/null Darwin (requires that $pid has open files): lsof -p $pid +r...
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How to reliably open a file in the same directory as a Python script

... 203 I always use: __location__ = os.path.realpath( os.path.join(os.getcwd(), os.path.dirname(__...
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JavaScript get window X/Y position for scroll

... The method jQuery (v1.10) uses to find this is: var doc = document.documentElement; var left = (window.pageXOffset || doc.scrollLeft) - (doc.clientLeft || 0); var top = (window.pageYOffset || doc.scrollTop) - (doc.clientTop || 0); That is: It...
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Is there an equivalent to e.PageX position for 'touchstart' event as there is for click event?

... 180 Kinda late, but you need to access the original event, not the jQuery massaged one. Also, since...
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Procedure expects parameter which was not supplied

... answered Dec 15 '08 at 15:20 HLGEMHLGEM 86.6k1111 gold badges103103 silver badges164164 bronze badges ...
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Are lists thread-safe?

...to concurrently access, the lists's data is not protected. For example: L[0] += 1 is not guaranteed to actually increase L[0] by one if another thread does the same thing, because += is not an atomic operation. (Very, very few operations in Python are actually atomic, because most of them can cau...
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how to rotate a bitmap 90 degrees

There is a statement in android canvas.drawBitmap(visiblePage, 0, 0, paint); 10 Answers ...
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How to sort objects by multiple keys in Python?

...ult: return mult * result else: return 0 return sorted(items, cmp=comparer) You can call it like this: b = [{u'TOT_PTS_Misc': u'Utley, Alex', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'Russo, Brandon', u'Total_Points': 96.0}, {u'TOT_PTS_Misc': u'...
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How to return a part of an array in Ruby?

...e out of range. a = [ "a", "b", "c", "d", "e" ] a[2] + a[0] + a[1] #=> "cab" a[6] #=> nil a[1, 2] #=> [ "b", "c" ] a[1..3] #=> [ "b", "c", "d" ] a[4..7] #=> [ "e" ] ...
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Unique (non-repeating) random numbers in O(1)?

I'd like to generate unique random numbers between 0 and 1000 that never repeat (i.e. 6 doesn't show up twice), but that doesn't resort to something like an O(N) search of previous values to do it. Is this possible? ...