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Is 0 a decimal literal or an octal literal?
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Yes, 0 is an Octal literal in C++.
As per the C++ Standard:
2.14.2 Integer literals [lex.icon]
integer-literal:
decimal-literal integer-suffixopt
octal-literal integer-suffixopt
hexadecimal-literal integer-suffixopt
decimal-literal:
nonzero-digit
decim...
Javascript Thousand Separator / string format [duplicate]
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15 Answers
15
Active
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Java: How to set Precision for double value? [duplicate]
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11 Answers
11
Active
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Best way to do nested case statement logic in SQL Server
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191
You could try some sort of COALESCE trick, eg:
SELECT COALESCE(
CASE WHEN condition1 THEN ...
Using ls to list directories and their total sizes
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1607
Try something like:
du -sh *
short version of:
du --summarize --human-readable *
Explan...
Does return stop a loop?
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221
Yes, return stops execution and exits the function. return always** exits its function immediate...
Turning live() into on() in jQuery
...ethods:
$(selector).live(events, data, handler); // jQuery 1.3+
$(document).delegate(selector, events, data, handler); // jQuery 1.4.3+
$(document).on(events, selector, data, handler); // jQuery 1.7+
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curl : (1) Protocol https not supported or disabled in libcurl
I'm trying to install the Rails environments on Ubuntu 11.04. When I launch the command rvm install 1.9.2 --with-openssl-dir=/usr/local the following error is received:
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Rounding up to next power of 2
...xt power of 2 number. For example if my input is 789, the output should be 1024. Is there any way of achieving this without using any loops but just using some bitwise operators?
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Remove all occurrences of a value from a list?
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Functional approach:
Python 3.x
>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter((2).__ne__, x))
[1, 3, 3, 4]
or
>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]
Python 2.x
>>> x = [1,2,3,2,2,2,3,4]
>...