大约有 45,000 项符合查询结果（耗时：0.0675秒） [XML]
Any way to Invoke a private method?
I have a class that uses XML and reflection to return Object s to another class.
7 Answers
...
Fastest hash for non-cryptographic uses?
...
CRC32 is pretty fast and there's a function for it: http://www.php.net/manual/en/function.crc32.php
But you should be aware that CRC32 will have more collisions than MD5 or even SHA-1 hashes, simply because of the reduced length (32 bits compare...
How to convert timestamps to dates in Bash?
I need a shell command or script that converts a Unix timestamp to a date. The input can come either from the first parameter or from stdin, allowing for the following usage patterns:
...
What is the Scala identifier “implicitly”?
...ave seen a function named implicitly used in Scala examples. What is it, and how is it used?
3 Answers
...
AppInventor2中的二进制数据以什么样的形式传递？字节列表、字节数组是什么...
1、byte[] 类型（字节数组）的字段：App Inventor 无法直接处理字节数组，但它们可以作为扩展之间的通用 Object 类型变量进行交换。
MQTT拓展中的字节数组的处理方式就是这种，直接转换成byte[]：
@SimpleFunction(description = "Publishe...
Casting a variable using a Type variable
...
Here is an example of a cast and a convert:
using System;
public T CastObject<T>(object input) {
return (T) input;
}
public T ConvertObject<T>(object input) {
return (T) Convert.ChangeType(input, typeof(T));
}
Edit:
Some p...
Run a Docker image as a container
... answered Aug 28 '13 at 21:14
AndyAndy
28.2k44 gold badges3636 silver badges4949 bronze badges
...
How to Iterate over a Set/HashSet without an Iterator?
...accessing the underlying structure that holds the data through reflection, and replicating the code provided by Set#iterator...
– assylias
Sep 17 '12 at 8:46
...
Merging dictionaries in C#
...ary(group => group.Key, group => group.First());
It's a bit ugly - and inefficient - but it's the quickest way to do it in terms of code. (I haven't tested it, admittedly.)
You could write your own ToDictionary2 extension method of course (with a better name, but I don't have time to think ...
Javascript objects: get parent [duplicate]
...
No. There is no way of knowing which object it came from.
s and obj.subObj both simply have references to the same object.
You could also do:
var obj = { subObj: {foo: 'hello world'} };
var obj2 = {};
obj2.subObj = obj.subObj;
var s = obj.subObj;
You now have three references, obj...