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In SQL, how can you “group by” in ranges?
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Neither of the highest voted answers are correct on SQL Server 2000. Perhaps they were using a different version.
Here are the correct versions of both of them on SQL Server 2000.
select t.range as [score range], count(*) as [number of occurences]
from (
select case
when score bet...
How can I suppress column header output for a single SQL statement?
... pete |
| 2 | john |
| 3 | mike |
+------+-------+
3 rows in set (0.00 sec)
Credit to ErichBSchulz for pointing out the -N alias.
To remove the grid (the vertical and horizontal lines) around the results use -s (--silent). Columns are separated with a TAB character.
mysql -s ...
use tes...
Determine if an HTML element's content overflows
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220
Normally, you can compare the client[Height|Width] with scroll[Height|Width] in order to detect ...
How can I use Bash syntax in Makefile targets?
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+500
From the GNU Make documentation,
5.3.1 Choosing the Shell
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The program used as the shell is taken from the ...
Is there a python equivalent of Ruby's 'rvm'?
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answered May 11 '10 at 16:27
Olivier VerdierOlivier Verdier
39.3k2626 gold badges9292 silver badges8989 bronze badges
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Set markers for individual points on a line in Matplotlib
...or example, using a dashed line and blue circle markers:
plt.plot(range(10), linestyle='--', marker='o', color='b')
A shortcut call for the same thing:
plt.plot(range(10), '--bo')
Here is a list of the possible line and marker styles:
================ ===============================
ch...
Is 161803398 A 'Special' Number? Inside of Math.Random()
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No, but it's based on Phi (the "golden ratio").
161803398 = 1.61803398 * 10^8 ≈ φ * 10^8
More about the golden ratio here.
And a really good read for the casual mathematician here.
And I found a research paper on random number generators that agrees with this assertion....
Iterating Over Dictionary Key Values Corresponding to List in Python
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– Zachary Ryan Smith
Jul 7 '18 at 0:18
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Round to at most 2 decimal places (only if necessary)
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Use Math.round(num * 100) / 100
Edit: to ensure things like 1.005 round correctly, we use
Math.round((num + Number.EPSILON) * 100) / 100
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Debugging iframes with Chrome developer tools
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answered Dec 20 '11 at 20:08
MetagrapherMetagrapher
7,44411 gold badge2121 silver badges3030 bronze badges
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