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C# '@' before a String [duplicate]
.... You can put an end of line in a string doing that, for instance:
String foo = "Hello\
There";
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How do I change the string representation of a Python class? [duplicate]
...class. Put this in your class definition:
def __str__(self):
return "foo"
You may also want to implement __repr__ to aid in debugging.
See here for more information:
Special Method Names - Basic Customization
sha...
What does the keyword “transient” mean in Java? [duplicate]
...ly.
Example from there, slightly modified (thanks @pgras):
public class Foo implements Serializable
{
private String saveMe;
private transient String dontSaveMe;
private transient String password;
//...
}
s...
Declare a block method parameter without using a typedef
...ally be preferred for more complicated cases.
– Fred Foo
Mar 30 '11 at 13:35
3
- ( void )myMethod...
Log.INFO vs. Log.DEBUG [closed]
...'s a good point. E.g. log.info("parse the widget text; ignore contents of 'foo'") serves as useful documentation when reading the code, even though it is also a log statement.
– Stew
Jan 25 '17 at 19:24
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sed fails with “unknown option to `s'” error [closed]
...d also works well with variables inside, i.e.: export var1=bar; sed -i "s@foo@${var1}@g". More info you can find into awesome sed documentation: grymoire.com/Unix/Sed.html
– Egel
Jun 28 '17 at 15:45
...
git how to disable push [duplicate]
...swered Apr 21 '12 at 15:30
Fred FooFred Foo
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Exported service does not require permission: what does it mean?
...
It will add it if you remove your tools:foo=bar statement, then when there is an error / warning, right click and use a quick fix to add the tools statement.
– Snicolas
Nov 14 '12 at 14:12
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php create object without class [duplicate]
..._decode, is passing a JSON-string: $object = json_decode('{"property": {"foo": "bar"}, "hello": "world"}');
– n.r.
Mar 14 '18 at 21:58
1
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Weird behavior with objects & console.log [duplicate]
...r logging in these cases is to log the individual values:
console.log(obj.foo, obj.bar, obj.baz);
Or JSON encode the object reference:
console.log(JSON.stringify(obj));
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