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Linux command to print directory structure in the form of a tree
Is there any linux command that I can call from a Bash script that will print the directory structure in the form of a tree, e.g.,
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How to open a web page from my application?
... security hole in your application if you were to accidentally get the URL from user input and not validate that it is a URI. They can then launch any application they want on your system.
– cdiggins
Nov 6 '15 at 17:49
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Copy Notepad++ text with formatting?
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Here is an image from notepad++ when you select text to copy as html.
and how the formatted text looks like after pasting it in OneNote (similar to any other app that supports "Paste Special"):
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Access to the path is denied
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You need to find out from the application pool for the website what is the identity it is running under (by default this is Application Pool Identity) and grant that the correct permissions.
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ORACLE 常用日期函数 - ORACLE - 清泛IT论坛，有思想、有深度
...日期。如果给出一负数，返回值日期之前几个月日期。
select add_months(to_date('20150201','yyyymmdd'), -1) from dual
结果：2015/1/1
相应的，加减天数add_days函数是不存在的，直接用+、-即可，例如：
select to_date('20150201','yyyymmdd')+1 from dual
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Saving results with headers in Sql Server Management Studio
...reopen SSMS after changing this option.
On the SQL Editor Toolbar you can select save to file without having to restart SSMS
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Save bitmap to location
I am working on a function to download an image from a web server, display it on the screen, and if the user wishes to keep the image, save it on the SD card in a certain folder. Is there an easy way to take a bitmap and just save it to the SD card in a folder of my choice?
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Sqlite: CURRENT_TIMESTAMP is in GMT, not the timezone of the machine
...a unix
timestamp 1092941466, and compensate
for your local timezone.
SELECT datetime(1092941466, 'unixepoch', 'localtime');
That didn't look like it fit my needs, so I tried changing the "datetime" function around a bit, and wound up with this:
select datetime(timestamp, 'localtime')
That...
MySQL/SQL: Group by date only on a Datetime column
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Cast the datetime to a date, then GROUP BY using this syntax:
SELECT SUM(foo), DATE(mydate) FROM a_table GROUP BY DATE(a_table.mydate);
Or you can GROUP BY the alias as @orlandu63 suggested:
SELECT SUM(foo), DATE(mydate) DateOnly FROM a_table GROUP BY DateOnly;
Though I don't think...
SQL Joins Vs SQL Subqueries (Performance)?
...e result i was looking for was 739 elements.
My query at first was this:
SELECT p.id,
p.fixedId,
p.azienda_id,
p.categoria_id,
p.linea,
p.tipo,
p.nome
FROM prodotto p
WHERE p.azienda_id = 2699 AND p.anno = (
SELECT MAX(p2.anno)
FROM prodotto p2
WHERE p2.fixed...