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How to get the difference between two arrays of objects in JavaScript
...4a55eff3-1e0d-4a81-9105-3ddd7521d642", display:"Jamsheer"}, { value:"644838b3-604d-4899-8b78-09e4799f586f", display:"Muhammed"}, { value:"b6ee537a-375c-45bd-b9d4-4dd84a75041d", display:"Ravi"}, { value:"e97339e1-939d-47ab-974c-1b68c9cfb536", display:"Ajmal"}, { value:"a63a6f77-c637-454e-abf2-dfb9b5...
Why does this Java code compile?
In method or class scope, the line below compiles (with warning):
14 Answers
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Javascript sort array by two fields
So the above code sorts the array by gsize - smallest to largest. It works good.
But if the gsize is the same I would like it to then sort by glow.
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Do regular expressions from the re module support word boundaries (\b)?
While trying to learn a little more about regular expressions, a tutorial suggested that you can use the \b to match a word boundary. However, the following snippet in the Python interpreter does not work as expected:
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Does the join order matter in SQL?
Disregarding performance, will I get the same result from query A and B below? How about C and D?
4 Answers
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Python syntax for “if a or b or c but not all of them”
...ve either zero or three command line arguments. (Either it runs on default behavior or needs all three values specified.)
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How to compare two colors for similarity/difference
I want to design a program that can help me assess between 5 pre-defined colors which one is more similar to a variable color, and with what percentage. The thing is that I don't know how to do that manually step by step. So it is even more difficult to think of a program.
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What is the best way to concatenate two vectors?
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AB.reserve( A.size() + B.size() ); // preallocate memory
AB.insert( AB.end(), A.begin(), A.end() );
AB.insert( AB.end(), B.begin(), B.end() );
share
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Why doesn't Java offer operator overloading?
Coming from C++ to Java, the obvious unanswered question is why didn't Java include operator overloading?
16 Answers
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Insert an element at a specific index in a list and return the updated list
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l.insert(index, obj) doesn't actually return anything. It just updates the list.
As ATO said, you can do b = a[:index] + [obj] + a[index:].
However, another way is:
a = [1, 2, 4]
b = a[:]
b.insert(2, 3)
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