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How to determine equality for two JavaScript objects?
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Nem>x m>t
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android splash screen sizes for ldpi,mdpi, hdpi, m>x m>hdpi displays ? - eg : 1024m>X m>768 pim>x m>els for ldpi
...esign 4 size images that fit for 4types of screens like ldpi, mdpi , hdpi, m>x m>hdpi . Can anyone tell me em>x m>act sizes in pim>x m>els for these screens so I can design in that size ?
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Histogram using gnuplot?
I know how to create a histogram (just use "with bom>x m>es") in gnuplot if my .dat file already has properly binned data. Is there a way to take a list of numbers and have gnuplot provide a histogram based on ranges and bin sizes the user provides?
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Android - Launcher Icon Size
For HDPI , m>X m>HDPI , etc. what should be the ideal size of the launcher icon? Should I have to create 9-Patch images for the icon to scale automatically, or would it be better to create separate icons?
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How to view or edit localStorage
I created a Chrome em>x m>tension and am using localStorage for storing data.
5 Answers
5
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Ruby optional parameters
.... The closest you can get is to pass nil:
ldap_get(base_dn, filter, nil, m>X m>)
However, this will set the scope to nil, not LDAP::LDAP_SCOPE_SUBTREE.
What you can do is set the default value within your method:
def ldap_get(base_dn, filter, scope = nil, attrs = nil)
scope ||= LDAP::LDAP_SCOPE_S...
Replacing blank values (white space) with NaN in pandas
...0.814772, 'baz', ' '],
[-0.222552, ' ', 4],
[-1.176781, 'qum>x m>', ' '],
], columns='A B C'.split(), indem>x m>=pd.date_range('2000-01-01','2000-01-06'))
# replace field that's entirely space (or empty) with NaN
print(df.replace(r'^\s*$', np.nan, regem>x m>=True))
Produces:
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How to elegantly check if a number is within a range?
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There are a lot of options:
int m>x m> = 30;
if (Enumerable.Range(1,100).Contains(m>x m>))
//true
if (m>x m> >= 1 && m>x m> <= 100)
//true
Also, check out this SO post for regem>x m> options.
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python plot normal distribution
...tats as stats
import math
mu = 0
variance = 1
sigma = math.sqrt(variance)
m>x m> = np.linspace(mu - 3*sigma, mu + 3*sigma, 100)
plt.plot(m>x m>, stats.norm.pdf(m>x m>, mu, sigma))
plt.show()
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improve th...
Average of 3 long integers
...s, so you 'lose' the remainder), and then divides the remainder:
long n = m>x m> / 3
+ y / 3
+ z / 3
+ ( m>x m> % 3
+ y % 3
+ z % 3
) / 3
Note that the above sample does not always work properly when having one or more negative values.
As dis...