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Matplotlib - Move X-Axis label downwards, but not X-Axis Ticks
... postfix: "",
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Should I be using object literals or constructor functions?
...If you want to add behaviour to your object, you can go with a constructor and add methods to the object during construction or give your class a prototype.
function MyData(foo, bar) {
this.foo = foo;
this.bar = bar;
this.verify = function () {
return this.foo === this.bar;
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How to tell if a string is not defined in a Bash shell script
...Autoconf, you'll find that they do not recommend combining terms with '-a' and do recommend using separate simple tests combined with &&. I've not encountered a system where there is a problem; that doesn't mean they didn't used to exist (but they are probably extremely rare these days, eve...
Move an item inside a list?
...already in the list to the specified position, you would have to delete it and insert it at the new position:
l.insert(newindex, l.pop(oldindex))
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Changing font size and direction of axes text in ggplot2
I am plotting a graph with a categorical variable on the x axis and a numerical variable on the y axis.
7 Answers
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C# Convert List to Dictionary
...ts you pick the key, the second one picks the value.
You can play with it and make values differ from the keys, like this:
var res = list.ToDictionary(x => x, x => string.Format("Val: {0}", x));
If your list contains duplicates, add Distinct() like this:
var res = list.Distinct().ToDictio...
Select a Dictionary with LINQ
I have used the "select" keyword and extension method to return an IEnumerable<T> with LINQ, but I have a need to return a generic Dictionary<T1, T2> and can't figure it out. The example I learned this from used something in a form similar to the following:
...
git cherry-pick says “…38c74d is a merge but no -m option was given”
I made some changes in my master branch and want to bring those upstream. when I cherry-pick the following commits however I get stuck on fd9f578 where git says:
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str performance in python
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'%s' % 100000 is evaluated by the compiler and is equivalent to a constant at run-time.
>>> import dis
>>> dis.dis(lambda: str(100000))
8 0 LOAD_GLOBAL 0 (str)
3 LOAD_CONST 1 (100000)
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Why does changing the sum order returns a different result?
...gnificant digits, where each addition is performed at "infinite" precision and then rounded to the nearest representable number. Here are two sums:
1/3 + 2/3 + 2/3 = (0.3333 + 0.6667) + 0.6667
= 1.000 + 0.6667 (no rounding needed!)
= 1.667 (where 1.6667 is rounded to...