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How can I sort generic list DESC and ASC?

... With Linq var ascendingOrder = li.OrderBy(i => i); var descendingOrder = li.OrderByDescending(i => i); Without Linq li.Sort((a, b) => a.CompareTo(b)); // ascending sort li.Sort((a, b) => b.CompareTo(a)); // descending sort Note that without Linq, ...
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Add new row to dataframe, at specific row-index, not appended?

The following code combines a vector with a dataframe: 4 Answers 4 ...
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“is” operator behaves unexpectedly with integers

Why does the following behave unexpectedly in Python? 11 Answers 11 ...
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See line breaks and carriage returns in editor

Does anyone know of a text editor on Linux that allows me to see line breaks and carriage returns? Does Vim support this feature? ...
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Parse date string and change format

I have a date string with the format 'Mon Feb 15 2010'. I want to change the format to '15/02/2010'. How can I do this? 9...
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python tuple to dict

For the tuple, t = ((1, 'a'),(2, 'b')) dict(t) returns {1: 'a', 2: 'b'} 6 Answers ...
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Python pandas: fill a dataframe row by row

The simple task of adding a row to a pandas.DataFrame object seems to be hard to accomplish. There are 3 stackoverflow questions relating to this, none of which give a working answer. ...
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Fill remaining vertical space with CSS using display:flex

...imple : DEMO section { display: flex; flex-flow: column; height: 300px; } header { background: tomato; /* no flex rules, it will grow */ } div { flex: 1; /* 1 and it will fill whole space left if no flex value are set to other children*/ background: gold; overf...
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Start an Activity with a parameter

...nt. Intent intent = new Intent(FirstActivity.this, SecondActivity.class); Bundle b = new Bundle(); b.putInt("key", 1); //Your id intent.putExtras(b); //Put your id to your next Intent startActivity(intent); finish(); Then grab the id in your new Activity: Bundle b = getIntent().getExtras(); int ...
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Implement Stack using Two Queues

A similar question was asked earlier there , but the question here is the reverse of it, using two queues as a stack. The question... ...