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Cast an instance of a class to a @protocol in Objective-C
... [vc protocolMethod];
}
The UIViewController <MyProtocol> * type-cast translates to "vc is a UIViewController object that conforms to MyProtocol", whereas using id <MyProtocol> translates to "vc is an object of an unknown class that conforms to MyProtocol".
This way the compiler wil...
Socket 错误返回码详解 - C/C++ - 清泛网 - 专注C/C++及内核技术
Socket 错误返回码详解Socket error 0 - Directly send errorSocket error 10004 - Interrupted function callSocket error 10013 - Permission...Socket error 0 - Directly send error
Socket error 10004 - Interrupted function call
Socket error 10013 - Permission denied
Socket error 10014 - Bad ad...
What does = +_ mean in JavaScript
...
r = +_;
+ tries to cast whatever _ is to a number.
_ is only a variable name (not an operator), it could be a, foo etc.
Example:
+"1"
cast "1" to pure number 1.
var _ = "1";
var r = +_;
r is now 1, not "1".
Moreover, according to the M...
TypeScript or JavaScript type casting
How does one handle type casting in TypeScript or Javascript?
3 Answers
3
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How to convert from System.Enum to base integer?
...g any System.Enum derived type to its corresponding integer value, without casting and preferably without parsing a string.
...
Select SQL Server database size
...y:
SELECT
database_name = DB_NAME(database_id)
, log_size_mb = CAST(SUM(CASE WHEN type_desc = 'LOG' THEN size END) * 8. / 1024 AS DECIMAL(8,2))
, row_size_mb = CAST(SUM(CASE WHEN type_desc = 'ROWS' THEN size END) * 8. / 1024 AS DECIMAL(8,2))
, total_size_mb = CAST(SUM(size) * 8. ...
Java Generics: Cannot cast List to List? [duplicate]
...
If you do have to cast from List<DataNode> to List<Tree>, and you know it is safe to do so, then an ugly way to achieve this is to do a double-cast:
List<DataNode> a1 = new ArrayList<DataNode>();
List<Tree> b1 =...
How do I convert a double into a string in C++?
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The boost (tm) way:
std::string str = boost::lexical_cast<std::string>(dbl);
The Standard C++ way:
std::ostringstream strs;
strs << dbl;
std::string str = strs.str();
Note: Don't forget #include <sstream>
...
How to cast/convert pointer to reference in C++
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Call it like this:
foo(*ob);
Note that there is no casting going on here, as suggested in your question title. All we have done is de-referenced the pointer to the object which we then pass to the function.
...
Converting stream of int's to char's in java
...et, or use InputStreamReader with the appropriate Charset instead.
Simply casting from int to char only works if you want ISO-8859-1, if you're reading bytes from a stream directly.
EDIT: If you are already using a Reader, then casting the return value of read() to char is the right way to go (aft...