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Is there a way to iterate over a dictionary?
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Yes, NSDictionary supports fast enumeration. With Objective-C 2.0, you can do this:
// To print out all key-value pairs in the NSDictionary myDict
for(id key in myDict)
NSLog(@"key=%@ value=%@", key, [myDict objectForKey:key]);
The alternate method (which you have to use if you're ...
How to add calendar events in Android?
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10 Answers
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contenteditable, set caret at the end of the text (cross-browser)
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answered Nov 21 '10 at 16:46
Tim DownTim Down
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Sort Dictionary by keys
...ys and values, like this:
let sortedKeysAndValues = sorted(dictionary) { $0.0 < $1.0 }
println(sortedKeysAndValues) // [(A, [1, 2]), (D, [5, 6]), (Z, [3, 4])]
EDIT2: The monthly changing Swift syntax currently prefers
let sortedKeys = Array(dictionary.keys).sort(<) // ["A", "D", "Z"]
The...
Using the Swift if let with logical AND operator &&
...r as? UITabBarController where tabBarController.viewControllers.count > 0 {
println("do stuff")
}
This uses the where clause.
Another example, this time casting AnyObject to Int, unwrapping the optional, and checking that the unwrapped optional meets the condition:
if let w = width a...
JavaScript - get the first day of the week from current date
... method of Date objects, you can know the number of day of the week (being 0=Sunday, 1=Monday, etc).
You can then subtract that number of days plus one, for example:
function getMonday(d) {
d = new Date(d);
var day = d.getDay(),
diff = d.getDate() - day + (day == 0 ? -6:1); // adjust whe...
How do you create a toggle button?
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edited Sep 24 '17 at 16:03
Geoman Yabes
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answere...
Inserting a text where cursor is using Javascript/jquery
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return;
}
var scrollPos = txtarea.scrollTop;
var strPos = 0;
var br = ((txtarea.selectionStart || txtarea.selectionStart == '0') ?
"ff" : (document.selection ? "ie" : false));
if (br == "ie") {
txtarea.focus();
var range = document.selection.createRange();
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Using CSS how to change only the 2nd column of a table
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answered Mar 29 '10 at 0:04
Nick Craver♦Nick Craver
580k125125 gold badges12551255 silver badges11351135 bronze badges
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Better way to shuffle two numpy arrays in unison
...ple: Let's assume the arrays a and b look like this:
a = numpy.array([[[ 0., 1., 2.],
[ 3., 4., 5.]],
[[ 6., 7., 8.],
[ 9., 10., 11.]],
[[ 12., 13., 14.],
[ 15., 16., 17.]]])
b = numpy.a...